Python map()是否允许索引？

Question

有没有办法获取列表的索引,哪个映射函数？我已经让地图几乎可以工作,但我能够访问long_words列表中的 特定项目

# full_chunk is a very long string of plaintext (eg:pages from a book)
# long_words is a list of words for which I wish to substitute other things

# works
for x in xrange(len(long_words)):
    full_chunk = full_chunk.replace(long_words[x],str(x))

# doesn't work :(
subber = lambda a,b,c: a.replace(b,c)
map(subber(full_chunk,long_words[long_words.index(x)],long_words.index(x)),long_words)

目前,我只是希望能够代替每一个字每一个出现的long_words,出现在full_chunk与所述字中的索引long_words列表.例如:

# example input
long_words = ['programming','pantaloons']
full_chunk = 'While programming, I prefer to wear my most vividly-hued pantaloons.'

# desired output (which is what the for loop gives me)
print(full_chunk)
'While 0, I prefer to wear my most vividly-hued 1.'

如果我需要提供更多信息,请告诉我,并提前感谢您的帮助!

Answer 1

使用enumerate(),你根本不需要map():

>>> long_words = ['programming', 'pantaloons']
>>> full_chunk = 'While programming, I prefer to wear my most vividly-hued pantaloons.'
>>> for i, word in enumerate(long_words):
...     full_chunk = full_chunk.replace(word, str(i))
...
>>> full_chunk
'While 0, I prefer to wear my most vividly-hued 1.'