我有一个data.frame如下:
>data
ID Orginal Modified
Sam_1 M K
Sam_1 K M
Sam_1 I J
Sam_1 M K
Sam_1 K M
Sam_2 K M
Sam_2 M K
Sam_3 J P
Sam_4 K M
Sam_4 M K
Sam_4 P J
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我想计算每个样本数量的时间M列中的"原始"在"修改"列中转换为K而"K"在"修改"列中将"原始"列转换为"M"并在制表符分隔文本中报告文件如下:
>newdata
ID M_to_K_counts K_to_M_counts
Sam_1 2 2
Sam_2 1 1
Sam_3 0 0
Sam_4 1 1
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我尝试了以下代码,但失败了:
counts=function()
{
for(i in 1:dim(rnaseqmut)[1])
{
mk_counts=0
km_counts=0
if(data$Original[i]=='M' & data$Modified[i]== 'K')
{
mk_counts=mk_counts+1
}
if(data$Original[i]=='K' & data$Modified[i]== 'M')
{
km_counts=km_counts+1
}
}
print(mk_counts)
print(km_counts)
}
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我怎样才能达到我想要的格式.
一种选择是使用data.table.将'data.frame'转换为'data.table'(setDT(data)).通过"ID"列分组,我们得到sum'原始'的'M'和'Modified'('MtoKcount')的'K'元素,类似地,通过反向得到'KtoMcount'.
library(data.table)
setDT(data)[, list(MtoKcount=sum(Orginal=='M' & Modified=='K'),
KtoMcount = sum(Orginal=='K' & Modified=='M')), by = ID]
# ID MtoKcount KtoMcount
#1: Sam_1 2 2
#2: Sam_2 1 1
#3: Sam_3 0 0
#4: Sam_4 1 1
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另一种选择是table来自base R.我们paste使用"ID"列(do.call(paste0, data[-1]))以外的列,并使用它来获取频率计数table.然后,我们将只有'KM'或'MK'作为列名的表输出('tbl')进行子集化
tbl <- table(data$ID,do.call(paste0, data[-1]))[,c('KM', 'MK')]
tbl
# KM MK
#Sam_1 2 2
#Sam_2 1 1
#Sam_3 0 0
#Sam_4 1 1
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正如评论中提到的@ user295691,我们可以在更改时更改列名paste.
tbl <- with(data, table(ID, paste0(Orginal, "_to_", Modified,"_counts")))
tbl[,c('K_to_M_counts', 'M_to_K_counts')]
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data <- structure(list(ID = c("Sam_1", "Sam_1", "Sam_1", "Sam_1",
"Sam_1",
"Sam_2", "Sam_2", "Sam_3", "Sam_4", "Sam_4", "Sam_4"), Orginal = c("M",
"K", "I", "M", "K", "K", "M", "J", "K", "M", "P"), Modified = c("K",
"M", "J", "K", "M", "M", "K", "P", "M", "K", "J")), .Names = c("ID",
"Orginal", "Modified"), class = "data.frame", row.names = c(NA,
-11L))
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