Axi*_*xil 27 ruby sql postgresql activerecord ruby-on-rails
Given a table that looks like this:
name
------
barry
dave
bill
dave
dave
barry
john
This query:
SELECT name, count(*) AS count FROM table GROUP BY name;
Will produce output like this:
name count
-------------
barry 2
dave 3
bill 1
john 1
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这里ActiveModel使用COUNT执行GROUP BY的正确Rails约定是什么?
the*_*tto 55
Distinct并Group By会给你不同的结果.要获得您希望使用的结果
Person.all.group(:name).count
(1.2ms) SELECT COUNT(*) AS count_all, name AS name FROM "people" GROUP BY "people"."name"
=> {"Dan"=>3, "Dave"=>2, "Vic"=>1}
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如上所述,group将返回哈希值.虽然不同只是返回总人数,见下文.
Person.all.distinct(:name).count
(0.4ms) SELECT DISTINCT COUNT(DISTINCT "people"."id") FROM "people"
=> 6
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小智 6
另外一个选择:
Person.select(:name, 'COUNT(name)').group(:name)
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这会生成一个具有属性计数的人员数组
请注意,接受的答案将返回一个哈希值:
Tagging.joins(:tag).group(:name).size
(0.4ms) SELECT COUNT(*) AS count_all, `name` AS name FROM `taggings` INNER JOIN `tags` ON `tags`.`id` = `taggings`.`tag_id` GROUP BY `name`
=> {"applesauce"=>1, "oranges"=>2}
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但是,如果您想在连接中返回计数以及来自不同表的一些列,该怎么办。然后你还需要使用 select ActiveRecord 查询:
collection = Tagging.select('COUNT(*) as total, taggings.taggable_id, taggings.taggable_type').joins(:tag).where(taggable_type: 'LineItem', taggable_id: ['5cad0dcc3ed1496086000031', '5cad0dcd3ed1496086000081'] ).group(:name)
collection.each do |item|
puts item.taggable_id
puts item.total
end
5cad0dcc3ed1496086000031
1
5cad0dcc3ed1496086000031
2
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使用第二种方法,您可以获取有关连接关系的其他详细信息,而无需任何其他查询或循环构造。