Ant*_*tex 17 datetime r strptime
想要将Time类更改为POSIXlt并仅提取小时分钟和秒
str(df3$Time)
chr [1:2075259] "17:24:00" "17:25:00" "17:26:00" "17:27:00" ...
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使用了strptime功能
df33$Time <- strptime(df3$Time, format = "%H:%M:%S")
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这给出了附加的日期/时间
> str(df3$Time)
POSIXlt[1:2075259], format: "2015-08-07 17:24:00" "2015-08-07 17:25:00" "2015-08-07 17:26:00" ...
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.
想要在不改变POSIXlt类的情况下提取时间.使用strftime函数
df3$Time <- strftime(df3$Time, format = "%H:%M:%S")
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但是这会将类转换回"char" -
> class(df3$Time)
[1] "character"
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如何将类设置为POSIX或数字来提取时间...
rmu*_*uc8 18
如果您的数据是
a <- "17:24:00"
b <- strptime(a, format = "%H:%M:%S")
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你可以使用lubridate以获得课程的结果integer
library(lubridate)
hour(b)
minute(b)
# > hour(b)
# [1] 17
# > minute(b)
# [1] 24
# > class(minute(b))
# [1] "integer"
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你可以使用它们来组合它们
# character
paste(hour(b),minute(b), sep=":")
# numeric
hour(b) + minute(b)/60
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例如.
如果您想对数据进行任何进一步操作,我不建议这样做.但是,如果要绘制结果,可能会很方便.
甲日期时间对象包含日期和时间; 你不能提取'只是时间'.所以你必须考虑你想要的东西:
两者都没有省略Date部分.拥有有效对象后,您可以选择仅显示时间.但是你不能使Date部分从表示中消失.
对此的“现代”tidyverse答案是使用hms::as_hms()
例如
library(tidyverse)
library(hms)
as_hms(1)
#> 00:00:01
as_hms("12:34:56")
#> 12:34:56
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或者,使用您的示例数据:
x <- as.POSIXlt(c("17:24:00", "17:25:00", "17:26:00", "17:27:00"), format = "%H:%M:%S")
x
#>[1] "2021-04-10 17:24:00 EDT" "2021-04-10 17:25:00 EDT" "2021-04-10 17:26:00 EDT" "2021-04-10 17:27:00 EDT"
as_hms(x)
# 17:24:00
# 17:25:00
# 17:26:00
# 17:27:00
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另请参阅此处的文档: https ://hms.tidyverse.org/reference/hms.html
这是我从日期时间对象中获取时间部分的习惯用法。我使用floor_date()from lubridate 来获取时间戳的午夜,并取时间戳和当天午夜的差值。我创建并存储一个在数据帧中hms提供的对象lubridate(我相信),因为该类的格式hh:mm:ss易于阅读,但底层值是秒的数值。这是我的代码:
library(tidyverse)
library(lubridate)
#>
#> Attaching package: 'lubridate'
#> The following object is masked from 'package:base':
#>
#> date
# Create timestamps
#
# Get timepart by subtacting the timestamp from it's floor'ed date, make sure
# you convert to seconds, and then cast to a time object provided by the
# `hms` package.
# See: https://www.rdocumentation.org/packages/hms/versions/0.4.2/topics/hms
dt <- tibble(dt=c("2019-02-15T13:15:00", "2019-02-19T01:10:33") %>% ymd_hms()) %>%
mutate(timepart = hms::hms(as.numeric(dt - floor_date(dt, "1 day"), unit="secs")))
# Look at result
print(dt)
#> # A tibble: 2 x 2
#> dt timepart
#> <dttm> <time>
#> 1 2019-02-15 13:15:00 13:15
#> 2 2019-02-19 01:10:33 01:10
# `hms` object is really a `difftime` object from documentation, but is made into a `hms`
# object that defaults to always store data in seconds.
dt %>% pluck("timepart") %>% str()
#> 'hms' num [1:2] 13:15:00 01:10:33
#> - attr(*, "units")= chr "secs"
# Pull off just the timepart column
dt %>% pluck("timepart")
#> 13:15:00
#> 01:10:33
# Get numeric part. From documentation, `hms` object always stores in seconds.
dt %>% pluck("timepart") %>% as.numeric()
#> [1] 47700 4233
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由reprex 包(v0.2.1)于 2019-02-15 创建
小智 6
您还可以使用该chron包仅提取一天中的时间:
library(chron)
# current date/time in POSIXt format as an example
timenow <- Sys.time()
# create chron object "times"
onlytime <- times(strftime(timenow,"%H:%M:%S"))
> onlytime
[1] 14:18:00
> onlytime+1/24
[1] 15:18:00
> class(onlytime)
[1] "times"
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