The*_*tan 8 django django-models
我最近从Django 1.6升级到Django 1.8.当我这样做时,我发现我无法再通过外键关系进行查找,如下所述:https: //docs.djangoproject.com/en/1.8/topics/db/queries/#lookups-那种跨度关系.
系统设置为有两个项目使用相同的数据库.(不是我的想法,而是我现在想要改变的东西.)最初创建和迁移模型的项目在升级后工作得很好,但另一个没有.每个模型文件都是相同的.
Models.py:
class Site(models.Model):
name = models.CharField(max_length=255)
class Meta:
app_label = 'project1'
class Page(models.Model):
title = models.CharField(max_length=255)
site = models.ForeignKey('Site')
class Meta:
app_label = 'project1'
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Django Shell的错误回溯:
>>> x = models.Site.objects.filter(page__id=1000)
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/manager.py", line 127, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/query.py", line 679, in filter
return self._filter_or_exclude(False, *args, **kwargs)
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/query.py", line 697, in _filter_or_exclude
clone.query.add_q(Q(*args, **kwargs))
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1314, in add_q
clause, require_inner = self._add_q(where_part, self.used_aliases)
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1342, in _add_q
allow_joins=allow_joins, split_subq=split_subq,
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1154, in build_filter
lookups, parts, reffed_expression = self.solve_lookup_type(arg)
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1035, in solve_lookup_type
_, field, _, lookup_parts = self.names_to_path(lookup_splitted, self.get_meta())
File "/home/user_name/project2/venv/local/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1401, in names_to_path
"Choices are: %s" % (name, ", ".join(available)))
FieldError: Cannot resolve keyword 'page' into field. Choices are: name, id
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在第一个项目中,相同的查询按预期工作:
>>> x = models.Site.objects.filter(page__id=1000)
[<Site: http://stackoverflow.com>]
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如果你related_name在`ForeignKey上设置一个怎么办?
class Page(models.Model):
site = models.ForeignKey('Site', related_name="pages") # Note the related_name here
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我在另一个项目上尝试了它,它的工作方式是有道理的:
>>> Site.objects.filter(pages__pk=42)
[<Site: http://stackoverflow.com>]
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如果你没有设置related_name,我认为默认是<model>_set.所以它应该是page_set.
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