And*_*rew 8 java android android-support-design
我在所有项目中使用android.support.design,今天我将其更新到最新版本
com.android.support:design:22.2.1
这是一个坏主意,因为我的项目崩溃了
java.lang.IndexOutOfBoundsException: Invalid index 0, size is 0
java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:255)
java.util.ArrayList.get(ArrayList.java:308)
android.support.design.widget.TabLayout.getTabAt(TabLayout.java:407)
android.support.design.widget.TabLayout.setupWithViewPager(TabLayout.java:585)
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经过一些调试,我发现这个方法有问题:
public void setupWithViewPager(@NonNull ViewPager viewPager) {
PagerAdapter adapter = viewPager.getAdapter();
if(adapter == null) {
throw new IllegalArgumentException("ViewPager does not have a PagerAdapter set");
} else {
this.setTabsFromPagerAdapter(adapter);
viewPager.addOnPageChangeListener(new TabLayout.TabLayoutOnPageChangeListener(this));
this.setOnTabSelectedListener(new TabLayout.ViewPagerOnTabSelectedListener(viewPager));
if(this.mSelectedTab == null || this.mSelectedTab.getPosition() != viewPager.getCurrentItem()) {
this.getTabAt(viewPager.getCurrentItem()).select();// ERROR On my code I'm used empty adapter
}
}
}
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但在之前的lib.2.2.2.0版本中,一切正常:
public void setupWithViewPager(ViewPager viewPager) {
PagerAdapter adapter = viewPager.getAdapter();
if(adapter == null) {
throw new IllegalArgumentException("ViewPager does not have a PagerAdapter set");
} else {
this.setTabsFromPagerAdapter(adapter);
viewPager.addOnPageChangeListener(new TabLayout.TabLayoutOnPageChangeListener(this));
this.setOnTabSelectedListener(new TabLayout.ViewPagerOnTabSelectedListener(viewPager));
}
}
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谁做了,谁可以受到惩罚呢?
请帮我找到Android支持设计库的开发人员.
小智 2
我很想对此发表评论,但我没有声誉。
看起来这个问题正在被跟踪并在未来的版本中修复:https://code.google.com/p/android/issues/detail ?id=180453
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