如何获取3个月的数据,不包括每个月的周末数据

Question

Select temp, DATE_FORMAT(temp,'%b-%d') from test
where temp between
    concat(year(now()),'-',month(now()) -3,'-', DATE_FORMAT(now(), '%d'))
        and
    (curdate());

我正在使用此查询获取3个月的数据,包括每周7天,但我没有按预期获得结果,如何通过此查询获取每周5天的数据并忽略数据库中的周末数据.

Answer 1

您可以使用该DAYOFWEEK函数,该函数返回范围从1(星期日)到的值7(星期六)的值:

SELECT temp, DATE_FORMAT(temp,'%b-%d') FROM test
WHERE
    DAYOFWEEK(temp) BETWEEN 2 AND 6
        AND
    temp BETWEEN
        CONCAT(YEAR(NOW()),'-',MONTH(NOW())-3,'-',DATE_FORMAT(NOW(), '%d'))
            AND
        (CURDATE());

但请注意,您选择过去3个月的数据的条件看起来有点可疑.做一些比较简单的事情可能更简单:

SELECT temp, DATE_FORMAT(temp,'%b-%d') FROM test
WHERE
    DAYOFWEEK(temp) BETWEEN 2 AND 6
        AND
    temp >= NOW()-INTERVAL 3 MONTH;