13 javascript jquery json google-api google-books
我正在尝试使用Google Books API构建书名推荐系统.不幸的是,与https://books.google.com相比,我得到的结果非常无关紧要.例如,这是我从搜索单词"sher"得到的列表(期待主要是像Sherlock Holmes这样的东西).
`She Said Yes;The Oh She Glows Cookbook;What Can She Know?;She-Wolf;Murder She Wrote;My Mother She Killed Me, My Father He Ate Me;22 Things a Woman Must Know If She Loves a Man with Asperger's Syndrome;Where She Danced;The Israeli-Palestinian Peace Negotiations, 1999-2001`
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如你所见,甚至没有最相关的标题.如果您在Google图书网站上输入"Sher",您将获得绝对正确的相关建议.我了解Google API吗?我的代码有什么问题?
var request = 'https://www.googleapis.com/books/v1/volumes';
var outputbookslistshow = 0;
$('#myTextArea').on('keyup', function(){
if(outputbookslistshow == 0){
outputbookslistshow = 1;
$('#outputgbooksrec').show(300); // it's a div for outputting titles
}
$('#outputgbooksrec').empty();
var keywords = $(this).val();
if(keywords.length > 0 ){
$.getJSON(request + '?q=' + keywords, function(response){
for (var i = 0; i < response.items.length; i++) {
var item = response.items[i];
document.getElementById("outputgbooksrec").innerHTML += "<br>"
+ "<div class='itembook'>" + item.volumeInfo.title + "</div>";
}
})
}
});
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jcu*_*nod 10
这是使用Google的https://suggestqueries.google.com/complete/search的工作小提琴
参数:
output/client # "toolbar" => xml, "firefox" => json, "chrome" => jsonp
ds # which site to search in ("bo" for books, "yt" for youtube...)
q # search term: "sher"
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查询:
https://suggestqueries.google.com/complete/search?output=firefox&ds=bo&q=sher
结果:
["sher",["sherlock holmes","sherrilyn kenyon","sherman alexie","sheryl sandberg","sherlock","sherlock holmes short stories","sherlock holmes book","sher o shayari","sherlock holmes novels","sher shah suri"]]
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首先要意识到的是,当谷歌提出建议时,如果你要输入,它们不会显示给你的结果.
如果您的查询中包含相关字词,则搜索结果是相关的.
建议假设您的查询不完整,因此将您的查询与其他查询进行比较,以猜测查询的完整版本可能是什么.
当我在http://books.google.com上搜索"sher"时,我看到的结果是:
这样做的原因是作者:前三,"乔治·谢"的情况下,并在第四个"芭芭拉·谢尔"的情形.这是期望的行为,因为当我搜索"sher"时,我不希望"Sherlock"结果掩埋"George Sher".
谷歌也有一种API供其建议.有关它的一些信息可以在这里找到.更重要的是,使用开发人员工具,您可以准确地看到Google正在做的事情.
使用开发者工具:检查https://books.google.com页面(Chrome中的CTRL+ SHIFT+ i).转到网络选项卡,等待所有内容都加载完毕.
当您开始输入时,Google会向服务器发出请求,您将在列表中看到这些请求.当我输入"sher"时,Google发送了此请求:
https://suggestqueries.google.com/complete/search?client=books&ds=bo&q=sher&callback=_callbacks_._1id33zyi5
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看看变量:
client = books
ds = bo
q = sher
callback = _callbacks_._1id33zyi5
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我通过观察这个请求,并通过阅读这些参数信息位拼凑起来的这个和这个.
CORS:因为您是来自不是google.com的域名的请求,所以您将收到Access-Control-Allow-Origin错误消息.这是一种试图阻止XSS的安全措施.要解决此问题,您需要使用JSONP.
使用jQuery,我们不必担心回调,所以让我们将客户端参数更改为chrome并使用此最终查询:
https://suggestqueries.google.com/complete/search?client=chrome&ds=bo&q=sher
下面的工作示例:在此示例中,您可能需要记下
"google:suggestrelevance"键,这是使用JSONP的额外好处(Google仅在JSONP数据中返回该信息).
var requestUrl = "https://suggestqueries.google.com/complete/search?client=chrome&ds=bo&q=";
var xhr;
$(document).on("input", "#query", function () {
typewatch(function () {
// Here's the bit that matters
var queryTerm = $("#query").val();
$("#indicator").show();
if (xhr != null) xhr.abort();
xhr = $.ajax({
url: requestUrl + queryTerm,
dataType: "jsonp",
success: function (response) {
$("#indicator").hide();
$("#response").html(syntaxHighlight(response));
}
});
}, 500);
});
/*
* --------- YOU ONLY NEED WHAT IS ABOVE THIS LINE ---------
*/
$(document).ready(function () {
$("#indicator").hide();
});
// Just for fun, some syntax highlighting...
// Credit: http://stackoverflow.com/a/7220510/123415
function syntaxHighlight(json) {
if (typeof json != 'string') {
json = JSON.stringify(json, undefined, 2);
}
json = json.replace(/&/g, '&').replace(/</g, '<').replace(/>/g, '>');
return json.replace(/("(\\u[a-zA-Z0-9]{4}|\\[^u]|[^\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/g, function (match) {
var cls = 'number';
if (/^"/.test(match)) {
if (/:$/.test(match)) {
cls = 'key';
} else {
cls = 'string';
}
} else if (/true|false/.test(match)) {
cls = 'boolean';
} else if (/null/.test(match)) {
cls = 'null';
}
return '<span class="' + cls + '">' + match + '</span>';
});
}
// And automatic searching (when you stop typing)
// Credit: http://stackoverflow.com/a/2219966/123415
var typewatch = (function () {
var timer = 0;
return function (callback, ms) {
clearTimeout(timer);
timer = setTimeout(callback, ms);
};
})();Run Code Online (Sandbox Code Playgroud)
/*
* Safe to ignore:
* This is just to make stuff look vaguely decent
*/
body {
padding: 10px;
}
div * {
vertical-align: top;
}
#indicator {
display: inline-block;
background: no-repeat center/100% url('http://galafrica.actstudio.ro/img/busy_indicator.gif');
width: 17px;
height: 17px;
margin: 3px;
}
/*
*
* CREDIT:
* http://stackoverflow.com/a/7220510/123415
*/
pre {
outline: 1px solid #ccc;
padding: 5px;
}
.string {
color: green;
}
.number {
color: darkorange;
}
.boolean {
color: blue;
}
.null {
color: red;
}
.key {
color: #008;
}Run Code Online (Sandbox Code Playgroud)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<input type=text id="query" placeholder="Start typing..." /><span id="indicator"></span>
</div>
<pre id="response"></pre>Run Code Online (Sandbox Code Playgroud)
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