PHP用数组中的值替换子字符串

Question

我有一个文字说:

$text = "An Elephant is an Elephant but an Elephant is not an Elephant"

我有一个阵列说:

$array = array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", "Seventh", "Eight", "Ninth");

在文中你可以看到有很多出现的"大象".我想要做的是我想用数组中的唯一值替换Elephant的出现,结果应该是这样的:

$result = "An Fifth is an Seventh but an First is not an Fourth"

到目前为止我试过这个:

$arr = array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", "Seventh", "Eight", "Ninth");
$text = "an elephant is an elephant but an elephant is not an elephant";
$array = explode(" ", $text);
$new_arr = array_diff($array, array("elephant"));
$text = implode(" ".$arr[array_rand($arr)]." ", $new_arr);
echo $text;

它输出这样的东西:

an First is First an First but First an First is First not First an

我怎么能这样？

An Fifth is an Seventh but an First is not an Fourth

Answer 1

在这,你为什么不尝试这个？

$arr = array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", "Seventh", "Eight", "Ninth");
$arrlength = count($arr);
$text = "an elephant is an elephant but an elephant is not an elephant";
$array = explode(" ", $text);
for ($i=0; $i < count($array); $i++) { 
    if ($array[$i]=="elephant")
    {
        $random_key = array_rand($arr, $arrlength);
        $array[$i] = $arr[$random_key[rand(0, $arrlength-1)]];
    }
}
$text = implode(" ", $array);
echo $text;