我一直在使用Swift 2的协议扩展和默认实现遇到问题.基本要点是我提供了一个协议方法的默认实现,我在一个实现协议的类中重写.从基类调用该协议扩展方法,然后调用我在派生类中重写的方法.结果是没有调用重写的方法.
我试图将这个问题提炼到最小的游乐场,这说明了下面的问题.
protocol CommonTrait: class {
func commonBehavior() -> String
}
extension CommonTrait {
func commonBehavior() -> String {
return "from protocol extension"
}
}
class CommonThing {
func say() -> String {
return "override this"
}
}
class ParentClass: CommonThing, CommonTrait {
override func say() -> String {
return commonBehavior()
}
}
class AnotherParentClass: CommonThing, CommonTrait {
override func say() -> String {
return commonBehavior()
}
}
class ChildClass: ParentClass {
override func say() -> String {
return super.say()
// it works if it calls `commonBehavior` here and not call `super.say()`, but I don't want to do that as there are things in the base class I don't want to have to duplicate here.
}
func commonBehavior() -> String {
return "from child class"
}
}
let child = ChildClass()
child.say() // want to see "from child class" but it's "from protocol extension”
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不幸的是,协议没有这种动态行为(尚未).
但是你可以通过实现和覆盖它来实现(commonBehavior()在类的帮助下).您还需要或另一个类符合哪个类是以下的超类:ParentClassChildClassCommonThingCommonTraitParentClass
class CommonThing: CommonTrait {
func say() -> String {
return "override this"
}
}
class ParentClass: CommonThing {
func commonBehavior() -> String {
// calling the protocol extension indirectly from the superclass
return (self as CommonThing).commonBehavior()
}
override func say() -> String {
// if called from ChildClass the overridden function gets called instead
return commonBehavior()
}
}
class AnotherParentClass: CommonThing {
override func say() -> String {
return commonBehavior()
}
}
class ChildClass: ParentClass {
override func say() -> String {
return super.say()
}
// explicitly override the function
override func commonBehavior() -> String {
return "from child class"
}
}
let parent = ParentClass()
parentClass.say() // "from protocol extension"
let child = ChildClass()
child.say() // "from child class"
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由于这只是您问题的简短解决方案,我希望它适合您的项目.
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