使用表的当前值更新语句

Aci*_*ibi 5 sql oracle

我想通过将一个字段的整数值递增1来更新表中的行.

目前不起作用,为什么?

Update htmIndex SET numObs = numObs+1 where ...
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APC*_*APC 15

简单案例,更新一行:

SQL> select name
  2         , age
  3  from t23
  4  where id = 2
  5  /

NAME                AGE
------------ ----------
MR KNOX              47

SQL> update t23
  2  set age = age + 6
  3  where id = 2
  4  /

1 row updated.

SQL> select name
  2         , age
  3  from t23
  4  where id = 2
  5  /

NAME                AGE
------------ ----------
MR KNOX              53

SQL>
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当列具有空值时更新行:

SQL> select name
  2         , age
  3  from t23
  4  where id = 6
  5  /

NAME                AGE
------------ ----------
SALLY

SQL> update t23
  2  set age=age+5
  3  where id = 6
  4  /

1 row updated.

SQL> select name
  2         , age
  3  from t23
  4  where id = 6
  5  /

NAME                AGE
------------ ----------
SALLY

SQL> update t23
  2  set age = nvl(age,0) +5
  3  where id = 6
  4  /

1 row updated.

SQL> select name
  2         , age
  3  from t23
  4  where id = 6
  5  /

NAME                AGE
------------ ----------
SALLY                 5

SQL>
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更新多行时同样简单:

 SQL> select name
   2         , age
   3  from t23
   4  where age > 20
   5  /

 NAME                AGE
 ------------ ----------
 MR KNOX              53
 FOX IN SOCKS         37
 CAT                  23
 LORAX               443

 SQL> update t23
   2  set age = age + 1
   3  where age > 20
   4  /

 4 rows updated.

 SQL> select name
   2         , age
   3  from t23
   4  where age > 20
   5  /

 NAME                AGE
 ------------ ----------
 MR KNOX              54
 FOX IN SOCKS         38
 CAT                  24
 LORAX               444

SQL>
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Ren*_*ene 5

它应该工作.但是,如果当前列值为null,则+ 1将返回null.

尝试: Update htmIndex SET numObs = nvl(numObs,0)+1 where ...