Julia TimeSeries包中的Readtimearray函数

Dan*_*uko 3 csv time-series julia

我想用readtimearray读取以下形式的csv文件:

"","ES1 Index","VG1 Index","TY1 Comdty","RX1 Comdty","GC1 Comdty"
"1999-01-04",1391.12,3034.53,66.515625,86.2,441.39
"1999-01-05",1404.86,3072.41,66.3125,86.17,440.63
"1999-01-06",1435.12,3156.59,66.4375,86.32,441.7
"1999-01-07",1432.32,3106.08,66.25,86.22,447.67
"1999-01-08",1443.81,3093.46,65.859375,86.36,447.06
"1999-01-11",1427.84,3005.07,65.71875,85.74,449.5
"1999-01-12",1402.33,2968.04,65.953125,86.31,442.92
"1999-01-13",1388.88,2871.23,66.21875,86.52,439.4
"1999-01-14",1366.46,2836.72,66.546875,86.73,440.01
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但是,这是我评估readtimearray("myfile.csv")时得到的结果

ERROR: `convert` has no method matching convert(::Type{UTF8String}, ::Float64)
 in push! at array.jl:460
 in readtimearray at /home/juser/.julia/v0.3/TimeSeries/src/readwrite.jl:25
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我没看到什么?

Vin*_*ynd 5

这看起来像是一个bug readtimearray.删除空行,但为了识别它们,代码只查看第一列.由于标题在第一列中有一个空字符串,因此将其删除...

将文件的标题更改为

"date","ES1 Index","VG1 Index","TY1 Comdty","RX1 Comdty","GC1 Comdty"
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解决了这个问题.