我有一个名为FLY的TABLE,我有一个名为FLY_NUM.im的列,试图在mysql查询中减少此列的值(在PHP中).这样的事情:
mysql_query("UPDATE fly SET `fly_Num` = `fly_Num` -1 WHERE fly_ID ='1' ");
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这是错误的!每次运行此查询时,FLY_NUM列设置为零.我可以做这样的事情吗?
您的查询有效且正确.也没有必要在-和之间留一个空格1.
测试用例:
CREATE TABLE fly (fly_id int, fly_num int);
INSERT INTO fly VALUES (1, 1);
INSERT INTO fly VALUES (1, 2);
INSERT INTO fly VALUES (1, 3);
INSERT INTO fly VALUES (1, 4);
INSERT INTO fly VALUES (1, 5);
INSERT INTO fly VALUES (1, 6);
INSERT INTO fly VALUES (1, 7);
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更新查询:
UPDATE fly SET `fly_Num` = `fly_Num` -1 WHERE fly_id ='1';
Query OK, 7 rows affected (0.00 sec)
Rows matched: 7 Changed: 7 Warnings: 0
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新表内容:
SELECT * FROM fly;
+--------+---------+
| fly_id | fly_num |
+--------+---------+
| 1 | 0 |
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 1 | 4 |
| 1 | 5 |
| 1 | 6 |
+--------+---------+
7 rows in set (0.00 sec)
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即使您varchar为fly_num列使用a ,它也可以工作:
CREATE TABLE fly (fly_id int, fly_num varchar(10));
INSERT INTO fly VALUES (1, '1');
INSERT INTO fly VALUES (1, '2');
INSERT INTO fly VALUES (1, '3');
INSERT INTO fly VALUES (1, '4');
INSERT INTO fly VALUES (1, '5');
INSERT INTO fly VALUES (1, '6');
INSERT INTO fly VALUES (1, '7');
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更新查询:
UPDATE fly SET `fly_Num` = `fly_Num` -1 WHERE fly_id ='1';
Query OK, 7 rows affected (0.00 sec)
Rows matched: 7 Changed: 7 Warnings: 0
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新表内容:
SELECT * FROM fly;
+--------+---------+
| fly_id | fly_num |
+--------+---------+
| 1 | 0 |
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 1 | 4 |
| 1 | 5 |
| 1 | 6 |
+--------+---------+
7 rows in set (0.00 sec)
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