YÒG*_*ÒGÎ 1 java string trim character sequence
输入将是,像,
iii,我非常喜欢java soooo
而预期的输出就像
嗨,我非常喜欢java
对于我的模糊编码如下,
List<String> wordList = Arrays.asList(word.split(""));
String previousCharacter;
boolean inneFlag = false;
boolean flag = false;
int iterator = 0;
int characterIterator = 0;
String finalizedWord = "";
previousCharacter = wordList.get(0);
for(String character : wordList){
if((wordList.size()-1)==characterIterator){
inneFlag = true;
}
if(flag){
if(character.equalsIgnoreCase(previousCharacter)){
iterator++;
if(inneFlag){
if(iterator>2){
finalizedWord = finalizedWord.substring(0,(finalizedWord.length()-iterator));
}
}
}else{
previousCharacter = character;
if(iterator>=2){
finalizedWord = finalizedWord.substring(0,(finalizedWord.length()-iterator));
}
iterator = 0;
}
}else{
flag = true;
}
characterIterator++;
finalizedWord += character;
}
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谁能给出更好的解决方案?
一个简单的正则表达式将完成这项工作.
string.replaceAll("([A-Za-z])\\1+", "$1");
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要么
string.replaceAll("(.)\\1+", "$1");
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