如何替换函数中if语句中的变量？

Question

print 'Welcome to the Pig Latin Translator!'

def pyg():
    if name.isalpha and len(name) > 0:
        print
    elif name.isdigit:
        print "This is an integer, not a string!"
        name = raw_input()
        pyg()
    elif len(name) <= 0:
        print "You typed nothing!"
        name = raw_input()
        pyg()
name = raw_input()
pyg()        

所以我得到了错误

UnboundLocalError:赋值前引用的局部变量'name'

我想要做的是当我的输入name是一个整数时,我输入要替换的东西name并再次运行该函数

Answer 1

为什么不name将函数作为参数传递给函数,并使函数接受参数？

print 'Welcome to the Pig Latin Translator!'

def pyg(name):
    if name.isalpha() and len(name) > 0:
        print
    elif name.isdigit():
        print "This is an integer, not a string!"
        name = raw_input()
        pyg()
    elif len(name) == 0:
        print "You typed nothing!"
        name = raw_input()
        pyg(name)

name = raw_input()
pyg(name)

顺便说一下,代码丢失()后isalpha,isdigit.并且长度永远不会变成负数.len(name) < 0没有意义.