jquery ajax中的url生成

Question

$(document).ready(function () {
    $(".linkDelete").click(function () {
        var userid = $(this).attr("id");
        console.debug("saurabh userid", userid);

        var url = "/delete?id=" + userid;
        var s = "SpringHibernateAnnotations";
        console.debug("saurabh url", url);
        $.ajax({
            url: s + "/delete?id=" + userid,
            success: function (data) {
                $('#result').html(data);
            }
        });
    });
});

我有这个jquery ajax函数生成这个URL GET http:// localhost:8080/SpringHibernateAnnotations/SpringHibernateAnnotations/delete？id = 253 404(Not Found)而不是它应该生成 http:// localhost:8080/SpringHibernateAnnotations/delete？ id = 253 404,如果我删除var s ="SpringHibernateAnnotations"; 并将我的url保存在ajax方法中作为url:"/ delete？id ="+ userid,它生成http:// localhost:8080/delete？id = 253,因为我无法进入application.So怎么能我生成这个正确的URL http:// localhost:8080/SpringHibernateAnnotations/delete？id = 253

Answer 1

/在base路径的url之前添加.-

var s= "/SpringHibernateAnnotations";

如果/在开始时不存在则将其视为relative路径.网址将是 - http://localhost:8080/SpringHibernateAnnotations/delete?id=253