Leo*_*ssi 2 python dictionary google-bigquery
我有一个带有一些嵌套值的字典,如下所示:
my_dict = {
"id": 1,
"name": "test",
"system": "x",
"date": "2015-07-27",
"profile": {
"location": "My City",
"preferences": [
{
"code": "5",
"description": "MyPreference",
}
]
},
"logins": [
"2015-07-27 07:01:03",
"2015-07-27 08:27:41"
]
}
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并且,我有一个 Big Query Table Schema,如下所示:
schema = {
"fields": [
{'name':'id', 'type':'INTEGER', 'mode':'REQUIRED'},
{'name':'name', 'type':'STRING', 'mode':'REQUIRED'},
{'name':'date', 'type':'TIMESTAMP', 'mode':'REQUIRED'},
{'name':'profile', 'type':'RECORD', 'fields':[
{'name':'location', 'type':'STRING', 'mode':'NULLABLE'},
{'name':'preferences', 'type':'RECORD', 'mode':'REPEATED', 'fields':[
{'name':'code', 'type':'STRING', 'mode':'NULLABLE'},
{'name':'description', 'type':'STRING', 'mode':'NULLABLE'}
]},
]},
{'name':'logins', 'type':'TIMESTAMP', 'mode':'REPEATED'}
]
}
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我想遍历所有原始的 my_dict 并根据架构的结构构建一个新的 dict。换句话说,迭代模式并从原始 my_dict 中选取正确的值。
要构建这样的新字典(请注意,不复制模式中不存在的字段“系统”):
new_dict = {
"id": 1,
"name": "test",
"date": "2015-07-27",
"profile": {
"location": "My City",
"preferences": [
{
"code": "5",
"description": "MyPreference",
}
]
},
"logins": [
"2015-07-27 07:01:03",
"2015-07-27 08:27:41"
]
}
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如果没有嵌套字段迭代简单的 dict.items() 和复制值,可能会更容易,但是如何构建新的 dict 以递归方式访问原始 dict?
我已经构建了一个递归函数来做到这一点。我不确定这是否更好,但有效:
def map_dict_to_bq_schema(source_dict, schema, dest_dict):
#iterate every field from current schema
for field in schema['fields']:
#only work in existant values
if field['name'] in source_dict:
#nested field
if field['type'].lower()=='record' and 'fields' in field:
#list
if 'mode' in field and field['mode'].lower()=='repeated':
dest_dict[field['name']] = []
for item in source_dict[field['name']]:
new_item = {}
map_dict_to_bq_schema( item, field, new_item )
dest_dict[field['name']].append(new_item)
#record
else:
dest_dict[field['name']] = {}
map_dict_to_bq_schema( source_dict[field['name']], field, dest_dict[field['name']] )
#list
elif 'mode' in field and field['mode'].lower()=='repeated':
dest_dict[field['name']] = []
for item in source_dict[field['name']]:
dest_dict[field['name']].append(item)
#plain field
else:
dest_dict[field['name']]=source_dict[field['name']]
format_value_bq(source_dict[field['name']], field['type'])
new_dict = {}
map_dict_to_bq_schema (my_dict, schema, new_dict)
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