smi*_*hyy 3 objective-c nsstring uitextview nsinteger ios
我有一个UITextView,我想限制用户可以输入的字符数.如果文本字段为空但我没有运气,我也试图显示警告.
textview.h
@property (nonatomic,strong) IBOutlet UITextView *textField;
@property (nonatomic, retain) NSString *userText;
textview.m
- (IBAction)next:(id)sender {
self.userText = self.textField.text;
if ([self.textField.text length] == 0) {
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error!"
message:@"Enter some text"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alertView show];
}
}
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这是文本限制方法似乎不起作用,
- (BOOL)textView:(UITextView *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string{
if(range.length + range.location > textField.text.length)
{
return NO;
} else {
NSUInteger newLength = [textField.text length] + [string length] - range.length;
return newLength <= 70;
return (textField.text.length <= 70);
}
}
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Nik*_*Nik 10
1)像这样在你的viewcontroller中添加UITextViewDelegate
@interface ViewController : UIViewController <UITextViewDelegate>
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每次用户在键盘上键入字符时,就在显示字符之前,调用以下方法.这是一个方便的位置,用于测试用户正在键入的字符,并禁止您要限制的特定字符.
TextView中:shouldChangeCharactersInRange:replacementString
2)然后编写以下代码.而不是140你可以把你想要的任何数字.
- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text
{
return textView.text.length + (text.length - range.length) <= 140;
}
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有关更多帮助,请查看UItextView
Swift 2.0解决方案
func textView(textView: UITextView, shouldChangeTextInRange range: NSRange, replacementText text: String) -> Bool {
return textView.text.characters.count + (text.characters.count - range.length) <= textViewLimit
}
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