Python:对多个dicts使用相同的键TypeError:'str'对象不支持项目赋值

Question

这是我的代码

sample_fh = dir + "sampleManifest.txt"
kids = {}
fid = {}
parents = {}
status = {}
sex = {}
with open(sample_fh) as f:
    for line in f:
            line = line.rstrip('\n')
            row = line.split('\t')
            fid = row[0]
            iid = row[1]
            relation  = row[5]
            status = row[6]
            sex = row[7]
            if relation != "Mother" and relation != "Father":
                    kids[iid] = 1
                    status[iid] = status
                    fid[iid] = fid
                    sex[iid]= row[7]
            if relation == "Mother" or relation == "Father":
                    parents[(fid,relation)]  = iid

我收到此错误:

status[iid] = status
TypeError: 'str' object does not support item assignment

不知道发生了什么事.以前的论坛说这个错误是在你改变字符串时引起的,但我很确定我没有改变任何字符串.

Answer 1

你重新分配status你的代码,status = row[6]因此它不再是一个字典,要么为你的字典使用另一个名字,要么在你的循环中改变状态,不要两者都使用它.

status = {} # starts as a dict
status = row[6] # now the name status points to something else i.e a str

Answer 2

fid = row[0]
iid = row[1]
relation = row[5]
status = row[6]
sex = row[7]

在这里,您将使用从文件中的行解析的简单值覆盖字典.因此,字典完全消失了.例如,status现在是一个字符串,所以当你以后这样做时status[iid],你使用索引访问来从字符串中获取单个字符.

您应该在那里重命名变量,这样就不会覆盖您的词典:

for line in f:
    line = line.rstrip('\n')
    row = line.split('\t')
    row_fid = row[0]
    iid = row[1]
    relation  = row[5]
    row_status = row[6]
    row_sex = row[7]
    if relation != "Mother" and relation != "Father":
            kids[iid] = 1
            status[iid] = row_status
            fid[iid] = row_fid
            sex[iid]= row_sex
    if relation == "Mother" or relation == "Father":
            parents[(row_fid, row_relation)]  = iid