SQL Server中的表和索引大小

Kam*_*shi 80 sql-server

我们可以有一个SQL查询,它基本上有助于查看SQl Server中的表和索引大小.

SQL Server如何维护表/索引的内存使用?

Rob*_*son 111

sp_spaceused为您提供所有索引组合的大小.

如果您想要表的每个索引的大小,请使用以下两个查询之一:

SELECT
    i.name                  AS IndexName,
    SUM(s.used_page_count) * 8   AS IndexSizeKB
FROM sys.dm_db_partition_stats  AS s 
JOIN sys.indexes                AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
WHERE s.[object_id] = object_id('dbo.TableName')
GROUP BY i.name
ORDER BY i.name

SELECT
    i.name              AS IndexName,
    SUM(page_count * 8) AS IndexSizeKB
FROM sys.dm_db_index_physical_stats(
    db_id(), object_id('dbo.TableName'), NULL, NULL, 'DETAILED') AS s
JOIN sys.indexes AS i
ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id
GROUP BY i.name
ORDER BY i.name
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结果通常略有不同,但在1%以内.


dev*_*vio 68

exec sp_spaceused无参数显示为整个数据库中的概要.foreachtable解决方案为每个表生成一个结果集 - 如果您有太多表,SSMS可能无法处理.

我创建了一个脚本,它通过收集表信息sp_spaceused并在单个记录集中显示摘要,按大小排序.

create table #t
(
  name nvarchar(128),
  rows varchar(50),
  reserved varchar(50),
  data varchar(50),
  index_size varchar(50),
  unused varchar(50)
)

declare @id nvarchar(128)
declare c cursor for
select '[' + sc.name + '].[' + s.name + ']' FROM sysobjects s INNER JOIN sys.schemas sc ON s.uid = sc.schema_id where s.xtype='U'

open c
fetch c into @id

while @@fetch_status = 0 begin

  insert into #t
  exec sp_spaceused @id

  fetch c into @id
end

close c
deallocate c

select * from #t
order by convert(int, substring(data, 1, len(data)-3)) desc

drop table #t
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  • 您的脚本只处理架构"dbo"中的表.如果我的数据库中有一个带有'Audit'模式的表,则需要像这样调用sp_spaceused:exec sp_spaceused'Review.Data'.因此,需要修改脚本以向其提供由模式名称(由点分隔)开头的表名,以便从其他模式返回有关表的数据. (4认同)

ear*_*g42 22

在SQL 2012上,在表级获取此信息变得非常简单:

SQL Management Studio - >右键单击Db - > Reports - > Standard Reports - > Disk by table!

请享用


Ben*_*n R 13

EXEC sp_MSforeachtable @command1="EXEC sp_spaceused '?'"
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  • 如果你发布代码,XML或数据样本,**请**在文本编辑器中突出显示这些行,然后单击编辑器工具栏上的"代码示例"按钮(`{}`),以便很好地格式化和语法突出显示它! (3认同)

小智 5

这篇文章已经很长时间了,但我想分享我的脚本:

WITH CteIndex
AS
(
SELECT 
     reservedpages = (reserved_page_count)
     ,usedpages = (used_page_count)
     ,pages = (
            CASE
                WHEN (s.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
                ELSE lob_used_page_count + row_overflow_used_page_count
            END
            )    
     ,s.object_id   
     ,i.index_id        
     ,i.type_desc AS IndexType
     ,i.name AS indexname
    FROM sys.dm_db_partition_stats s
    INNER JOIN sys.indexes i ON s.[object_id] = i.[object_id] AND s.index_id = i.index_id   
)
SELECT DISTINCT
DB_NAME(DB_ID()) AS DatabaseName
,o.name AS TableName
,o.object_id
,ct.indexname
,ct.IndexType
,ct.index_id
, IndexSpace = LTRIM (STR ((CASE WHEN usedpages > pages THEN CASE WHEN ct.index_id < 2 THEN  pages ELSE (usedpages - pages) END ELSE 0 END) * 8, 15, 0) + ' KB')
FROM CteIndex ct
INNER JOIN sys.objects o ON o.object_id = ct.object_id
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL , NULL) ps ON ps.object_id = o.object_id
AND ps.index_id = ct.index_id
ORDER BY name ASC
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这适用于:

  • SQL Server(从 2008 开始)
  • 包括每个当前数据库的所有表的信息

  • 这很棒。我对“IndexSpace”列进行的一项更改是使其保持数字状态,这样就可以轻松按大小排序,如下所示:`, IndexSpaceKB = (CASE WHENusedpages &gt;pages THEN CASE WHEN ct.index_id &lt; 2 THENpages ELSE (usedpages - 页)END ELSE 0 END)* 8` (2认同)

Ale*_*lex 5

--Gets the size of each index for the specified table
DECLARE @TableName sysname = N'SomeTable';

SELECT i.name AS IndexName
      ,8 * SUM(s.used_page_count) AS IndexSizeKB
FROM sys.indexes AS i
    INNER JOIN sys.dm_db_partition_stats AS s 
        ON i.[object_id] = s.[object_id] AND i.index_id = s.index_id
WHERE s.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;

SELECT i.name AS IndexName
      ,8 * SUM(a.used_pages) AS IndexSizeKB
FROM sys.indexes AS i
    INNER JOIN sys.partitions AS p 
        ON i.[object_id]  = p.[object_id] AND i.index_id = p.index_id
    INNER JOIN sys.allocation_units AS a 
        ON p.partition_id = a.container_id
WHERE i.[object_id] = OBJECT_ID(@TableName, N'U')
GROUP BY i.name
ORDER BY i.name;
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