Les*_* YJ 2 java arrays sorting
import java.util.*;
import java.util.Random;
class ArraySorting {
public static void main(String[]args) {
ArrayList<Integer> arr = new ArrayList<Integer>();
Random generate = new Random();
for (int nums = 0; nums < 20; nums++) {
int randomnumbers = generate.nextInt(50);
arr.add(randomnumbers);
}
System.out.println("First list of 20 generated numbers: ");
System.out.println(arr);
System.out.println("");
int dupe = 0;
for (int n = 0; n < arr.size(); n++) {
Integer check1 = arr.get(n);
for (int n2 = n+1; n2 < arr.size(); n2++) {
Integer check2 = arr.get(n2);
//remove second num if two numbers akike
if (check1.equals(check2)) {
arr.remove(check2);
n2 = n2-1;
dupe = 1;
}
}
n = n-dupe;
dupe = 0;
}
System.out.println("Duplicates: " + (20 - arr.size()));
for (int n3 = arr.size(); n3 < 20; ++n3) {
int randomnumbers = generate.nextInt(50);
arr.add(randomnumbers);
//check for duplicates again
for (int n = 0; n < arr.size(); n++) {
Integer check1 = arr.get(n);
for (int n2 = n+1; n2 < arr.size(); n2++) {
Integer check2 = arr.get(n2);
if (check1.equals(check2)) {
arr.remove(check2);
n2 = n2-1;
dupe = 1;
}
}
n = n - dupe;
dupe = 0;
}
}
//before sort
System.out.println(arr);
System.out.println("");
for(int a=0; a<20; a++){
for (int b = 0; b < 19; b++) {
if(arr[b] > arr[b+1]){
int temporary = arr[b];
arr[b] = arr[b+1];
arr[b+1] = temporary;
}
}
}
System.out.println("\nSorted Array:\n");
for (int a = 0; a < 20; a++) {
System.out.println("Array [" + a + "]: " + arr[a]);
}
}
}
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任何人都可以告诉我我为这个做错了什么,我似乎无法生成最后一部分.不应该是ArrayList arr = new ArrayList(); 与arr [b]工作的最后一部分一样运行?我是Java的新手,如果提供解决方案的简单解释/隐喻,我将非常感激.
PS:我不打算使用像Collection这样的库排序函数,我需要在最后一部分使用排序方法.
arr[a]
是访问数组元素的语法.对于ArrayList
你使用的arr.get(a)
.并为a分配值ArrayList
,您可以使用arr.set(b,value)
.您不能使用赋值运算符.