use*_*335 3 excel python-2.7 xlsxwriter
有没有办法使用 XlsxWriter 按名称获取工作表?
import win32com.client, types, pythoncom, sys, os, string
import xlsxwriter
xlApp = win32com.client.Dispatch("Excel.Application")
for file in os.listdir("C:\Users\\Desktop\Escel"):
if file.endswith(".xlsx"):
fileName = file
books = xlApp.Workbooks.Open(r"C:\\Users\\Desktop\\Escel\\" + str(fileName))
ws = books.sheet_by_name("2015 Data")
#ws = books.Worksheets[0]
ws.Visible = 1
fileName.replace(".xlsx","")
ws.ExportAsFixedFormat(0, r"C:\\Users\\Desktop\\PDF\\" + str(fileName) + str(".pdf"))
books.Close(True, r"C:\\Users\\Desktop\\Escel\\" + str(fileName))
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XlsxWriter 0.8.7 现在提供了一种方法来做到这一点。例如:
worksheet = workbook.get_worksheet_by_name("Sheet1")
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请参阅:http : //xlsxwriter.readthedocs.io/workbook.html#get_worksheet_by_name