拆分列表每n个元素和cbind,然后是rbind切片

Question

我想切片列表中的每个n元素,cbind切片,然后rbind切片.

我可以使用下面的代码执行此操作(n = 10个元素,列表长度为30个元素).我'手动'选择列表中的每10个元素,然后选择cbind这10个元素切片.然后我rbind那些cbinded切片.

但是,我认为可以通过l*plyin plyr或者dplyr至少其中一些来实现这一点.对于初学者,我现在不知道如何选择列表中的每个n元素,并且似乎不知道找到这个答案的适当搜索词.

dl <- list(c(2L, 1L, 3L, 2L, 1L, 1L, 3L), c(1L, 1L, 2L, 1L, 1L, 2L, 
1L), c(1L, 1L, 2L, 2L, 3L, 3L, 3L), c(1L, 1L, 2L, 2L, 3L, 3L, 
3L), c(1L, 1L, 2L, 2L, 3L, 3L, 3L), c(1L, 1L, 2L, 2L, 3L, 3L, 
1L), c(1L, 1L, 2L, 2L, 3L, 3L, 3L), c(1L, 3L, 2L, 1L, 3L, 2L, 
1L), c(3L, 1L, 2L, 3L, 3L, 1L, 3L), c(3L, 2L, 1L, 1L, 3L, 3L, 
1L), c(1L, 1L, 2L, 2L, 2L, NA, NA), c(1L, 1L, 2L, 2L, 3L, NA, 
NA), c(1L, 1L, 2L, 2L, 3L, NA, NA), c(1L, 1L, 2L, 2L, 3L, NA, 
NA), c(1L, 1L, 2L, 2L, 3L, NA, NA), c(1L, 1L, 2L, 2L, 3L, NA, 
NA), c(1L, 1L, 2L, 2L, 3L, NA, NA), c(1L, 1L, 2L, 2L, 3L, NA, 
NA), c(1L, 1L, 2L, 2L, 3L, NA, NA), c(2L, 1L, 2L, 1L, 1L, NA, 
NA), c(2L, 3L, 1L, 2L, 1L, 2L, NA), c(1L, 1L, 2L, 2L, 1L, 3L, 
NA), c(1L, 1L, 2L, 2L, 3L, 3L, NA), c(1L, 1L, 2L, 2L, 3L, 3L, 
NA), c(1L, 1L, 2L, 2L, 3L, 3L, NA), c(1L, 1L, 2L, 2L, 3L, 3L, 
NA), c(1L, 1L, 2L, 2L, 3L, 3L, NA), c(1L, 1L, 2L, 2L, 3L, 3L, 
NA), c(1L, 1L, 2L, 2L, 3L, 3L, NA), c(1L, 1L, 2L, 2L, 3L, 3L, 
NA)) 

# slice list 'manually' cbind those slices
dl1 <- dl[1:10]
dl1.c <- do.call("cbind", dl1)
dl2 <- dl[11:20]
dl2.c <- do.call("cbind", dl2)
dl3 <- dl[21:30]
dl3.c <- do.call("cbind", dl3)

# rbind the cbind slices for result
ans <- as.data.frame(rbind(dl1.c, dl2.c, dl3.c)) # ans as df
# ans <- rbind(dl1.c, dl2.c, dl3.c)

Answer 1

尝试

do.call(mapply, c(cbind, split(dl, cut(seq_along(dl), length(dl)/10, labels = FALSE))))