使用空格和字符将字符串拆分为Oracle中的分隔符和regexp_substr

Question

我正在尝试用regexp_subtr拆分字符串,但我无法使它工作.

所以,首先,我有这个查询

select regexp_substr('Helloworld - test!' ,'[[:space:]]-[[:space:]]') from dual

非常好地提取我的分隔符 - 空白 - 空白

但是,当我尝试使用此选项拆分字符串时,它只是不起作用.

select regexp_substr('Helloworld - test!' ,'[^[[:space:]]-[[:space:]]]+')from dual

查询什么都不返回.

将非常感谢帮助!谢谢

Answer 1

SQL小提琴

Oracle 11g R2架构设置:

CREATE TABLE TEST( str ) AS
          SELECT 'Hello world - test-test! - test' FROM DUAL
UNION ALL SELECT 'Hello world2 - test2 - test-test2' FROM DUAL;

查询1:

SELECT Str,
       COLUMN_VALUE AS Occurrence,
       REGEXP_SUBSTR( str ,'(.*?)([[:space:]]-[[:space:]]|$)', 1, COLUMN_VALUE, NULL, 1 ) AS split_value
FROM   TEST,
       TABLE(
         CAST(
           MULTISET(
             SELECT LEVEL
             FROM   DUAL
             CONNECT BY LEVEL < REGEXP_COUNT( str ,'(.*?)([[:space:]]-[[:space:]]|$)' )
           )
           AS SYS.ODCINUMBERLIST
         )
       )

结果:

|                               STR | OCCURRENCE |  SPLIT_VALUE |
|-----------------------------------|------------|--------------|
|   Hello world - test-test! - test |          1 |  Hello world |
|   Hello world - test-test! - test |          2 |   test-test! |
|   Hello world - test-test! - test |          3 |         test |
| Hello world2 - test2 - test-test2 |          1 | Hello world2 |
| Hello world2 - test2 - test-test2 |          2 |        test2 |
| Hello world2 - test2 - test-test2 |          3 |   test-test2 |