ino*_*not 8 iphone xcode parsing json
我有这样的JSON对象:
{ "data":
{"array":
["2",
{"array":
[
{"clientId":"1","clientName":"Andy","job":"developer"},
{"clientId":"2","clientName":"Peter","job":"carpenter"}
]
}
]
},
"message":"MSG0001:Success",
"status":"OK"
}
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我想使用JSON-Framework获取array [0] value(2)和array [1]值(clientId,clientName,job).你知道怎么做吗?
dea*_*rne 21
假设您已按照说明将 JSON-Framework 安装到项目中,以下是您使用它的方法(取自此处的文档):
// Parse the string into JSON
NSDictionary *json = [myString JSONValue];
// Get the objects you want, e.g. output the second item's client id
NSArray *items = [json valueForKeyPath:@"data.array"];
NSLog(@" client Id : %@", [[items objectAtIndex:1] objectForKey:@"clientId"]);
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谢谢你的回答,我的问题解决了,我从你的代码中修改了一下,这里有:
// Parse the string into JSON
NSDictionary *json = [myString JSONValue];
// Get all object
NSArray *items = [json valueForKeyPath:@"data.array"];
NSArray *array1 = [[items objectAtIndex:1] objectForKey:@"array"];
NSEnumerator *enumerator = [array1 objectEnumerator];
NSDictionary* item;
while (item = (NSDictionary*)[enumerator nextObject]) {
NSLog(@"clientId = %@", [item objectForKey:@"clientId"]);
NSLog(@"clientName = %@",[item objectForKey:@"clientName"]);
NSLog(@"job = %@", [item objectForKey:@"job"]);
}
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