我有这样的DU:
type Food =
| Beer
| Bacon
| Apple
| Cherry
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如果食物是水果,我想给DU添加一个特征来标记.我首先想到的是这样的事情:
type NonFruit = NonFruit
type Fruit = Fruit
type Food =
| Beer of NonFruit
| Bacon of NonFruit
| Apple of Fruit
| Cherry of Fruit
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然后像这样的方法:
让fruitChecker(myFood:Food)=将myFood与|匹配 :?NonFruit - >"不"| :?水果 - >"是"
但是编译器对我大喊大叫:
"食物"类型没有任何正确的子类型,不能用作来源
我是否错误地接近了这个问题?
谢谢
或者,使用活动模式:https://msdn.microsoft.com/en-us/library/dd233248.aspx
type Food =
| Beer
| Bacon
| Apple
| Cherry
let (|NonFruit|Fruit|) =
function
| Beer | Bacon -> NonFruit
| Apple | Cherry -> Fruit
let fruitChecker = function | NonFruit -> "No" | Fruit -> "Yes"
[Beer;Bacon;Apple;Cherry] |> List.iter(fun x -> printfn "%s" (fruitChecker x))
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打印:
No
No
Yes
Yes
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链接:https://dotnetfiddle.net/oRYDs6