使用int(str)

Question

我想知道是否有更简单的方法来做到这一点？

if '0' in next or '1' in next or '2' in next or '3' in next or '4' in next or '5' in next or '6' in next or '7' in next or '8' in next or '9' in next:
        how_much = int(next)

Answer 1

使用异常处理; 请求宽恕而不是许可:

try:
    how_much = int(next)
except ValueError:
    # handle the conversion failing; pass means 'ignore'
    pass