在C++中将一串数字转换为double

Question

在这里,我试图将一串数字转换为相应的双数字.

double string_to_double ( const char* str)
{

int i = 0;
double* num = (double *)malloc(sizeof(double));
*num = 0;
int fract_fact = 10;
int size = strlen(str);

if ( str[0] != '.')  // if its not starting with a point then take out the first decimal digit and place it in the number instead of 0.

  *num = (str[i] - '0');


for ( i = 1; i < size; ++i){

    if ( str[i] == '.'){

        i++;

        for (int j = i; j < size; ++j){ // after encountering point the rest of the part is fractional.


            *num += (str[j] - '0') / fract_fact; // summing up the next fractional digit.
            fract_fact *= 10; // increasing the farct_fact by a factor of 10 so that next fractional digit can be added rightly.
        }

        break;
    }

    *num = *num * 10 + ( str[i] - '0');
}

return *num;
}

当我从main调用它时如下

cout << string_to_double("123.22");

它的输出是

123

但为什么？我究竟做错了什么？

Answer 1

*num += (str[j] - '0') / fract_fact;

应该

*num += (str[j] - '0') / (double)fract_fact;

您的版本执行整数运算,总是计算为零.

不是你问的问题,但为什么要分配num？

double num;

num = ...

return num;

更简单,它不会泄漏内存.