将NSTimInterval转换为Integer Swift

Question

我需要将NSTimeInterval类型的变量(我知道是Double)转换为Integer.我已经尝试过这里的解决方案:如何将NSTimeInterval转换为int？,没有成功.任何人都可以在Swift中提供有关如何执行此操作的任何建议吗？以下是我的功能:

func getHKQuantityData(sampleType: HKSampleType, timeUnit: NSCalendarUnit, startDate: NSDate, endDate: NSDate, completion: (Void -> Void)) -> [(NSDate, Double)] {
    var startTime = 0
    var endTime = 0
    var repeat: NSTimeInterval
    var returnValue: [(NSDate, Double)] = []
    var queryType: String = ""
    var predicate: NSPredicate!
    let timeInterval = endDate.timeIntervalSinceDate(startDate)
    switch sampleType {
    case HKSampleType.quantityTypeForIdentifier(HKQuantityTypeIdentifierStepCount):
        queryType = "step"
    case HKSampleType.quantityTypeForIdentifier(HKQuantityTypeIdentifierHeight):
        queryType = "height"
    case HKSampleType.quantityTypeForIdentifier(HKQuantityTypeIdentifierBodyMass):
        queryType = "weight"
    case HKSampleType.quantityTypeForIdentifier(HKQuantityTypeIdentifierBodyMassIndex):
        queryType = "bmi"
    default:
        println("No recognized type")
    }

    switch timeInterval {
    // 1. Case for seconds
    case 0...59:
        predicate = HKQuery.predicateForSamplesWithStartDate(NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitSecond, value: startTime, toDate: NSDate(), options: nil), endDate: NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitSecond, value: startTime, toDate: NSDate(), options: nil), options: .None)
        repeat = timeInterval
    // 2. Case for minutes
    case 61...3599:
        predicate = HKQuery.predicateForSamplesWithStartDate(NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitMinute, value: startTime, toDate: NSDate(), options: nil), endDate: NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitMinute, value: startTime, toDate: NSDate(), options: nil), options: .None)
        repeat = round(timeInterval / 60)
    // 3. Case for Hours
    case 3600...86399:
        predicate = HKQuery.predicateForSamplesWithStartDate(NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitHour, value: startTime, toDate: NSDate(), options: nil), endDate: NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitHour, value: startTime, toDate: NSDate(), options: nil), options: .None)
        repeat = round(timeInterval / 3600)
    // 4. Default for Days
    default:
        predicate = HKQuery.predicateForSamplesWithStartDate(NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitDay, value: startTime, toDate: NSDate(), options: nil), endDate: NSCalendar.currentCalendar().dateByAddingUnit(.CalendarUnitDay, value: startTime, toDate: NSDate(), options: nil), options: .None)
        repeat = round(timeInterval / 86400)
    }
    /*
    for x in 1...repeat {

    }
    */


    // Returns one data point for each timeUnit between startDate and endDate
    // array of tuples - (date, double)

    return returnValue
}

Answer 1

胁迫:

let i = Int(myTimeInterval)

编辑在评论中,正确地指出这种方法可能会失败(并崩溃),因为包含的Double myTimeInterval可能大于Int的最大大小,从而导致溢出.

在Swift 4之前,处理这种可能性非常困难.但是Swift 4引入了两个新的Int初始化器来解决这个问题:

• init(exactly:)- 这是一个可用的初始化程序,因此它返回一个可选的Int nil.

• init(clamping:) - 这总是成功的,因为如果由于溢出而失败,最大的合法Int被替换.