输出不按升序排序.这是我得到的代码和输出.
实际输出是:
Amy Jose Jeremy Alice Patrick Alan Amy Jeremy Helen Alexi
虽然预期产量是:
Amy, Alice, Jeremy, jose, Patrick Alan, Amy, Alexi, Helen, Jeremy
代码是:
public class MyFriends
{
static Set<String> names = new TreeSet<String>();
public MyFriends()
{
super();
names = new TreeSet<String>();
}
public static void exampleMethod()
{
String[] name1 = {"Amy", "Jose", "Jeremy", "Alice", "Patrick"};
String[] name2 = { "Alan", "Amy", "Jeremy", "Helen", "Alexi"};
for (int i = 0; i < name1.length; i++)
{
names.add(name1[i]);
}
for (String aString : name1)
{
System.out.print(" " + aString);
}
for (int i = 0; i < name2.length; i++)
{
names.add(name2[i]);
}
for (String bString : name2)
{
System.out.print(" " + bString);
}
}
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你现在只是再次写出数组......将数组的内容添加到a TreeSet中不会改变数组.
而不是两个块写出数组,你应该有一个,在最后:
for (String name : names)
{
System.out.print(" " + name);
}
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如果您确实需要两行输出,则应使用两个TreeSet实例.
如果要对数组进行排序,则应该对它们进行排序.当你向a添加一个值时TreeSet,它既不知道也不关心它来自何处.它只是对字符串对象的引用(在本例中).
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