如何在Angular UI Bootstrap中查看模态是否已打开

Question

我正在使用Angular UI Bootstrap.如果一个模态打开,我想显示true.如果它没有打开,我想显示false.有没有办法在HTML中执行此操作？

我尝试使用以下代码,但这是错的:

<code>myForm.$modalStack.opened={{myForm.$modalStack.opened}}</code>

有关如何正确执行此操作的任何想法？

在我用来触发模态的相关代码下面:

HTML:

<button ng-click="myForm.agreement()">

控制器中的代码:

.controller('MyFormCtrl',
  function ($location, $stateParams, $modal, $scope, $http) {
    var myForm = this;
    // . . . 

   myForm.agreement = agreement;

   function agreement() {

       $modal.open({

          templateUrl: 'views/agreement.html'
  })
});

Answer 1

opened返回的属性$modal.open是您可以接受的承诺.

所以,使用他们的例子,请看这里 - http://plnkr.co/edit/PsEqTIy8CDUU88HMLxbC?p=preview

$scope.modalOpen = false;
$scope.open = function (size) {
    var modalInstance =  $modal.open({
        animation: $scope.animationsEnabled,
        templateUrl: 'myModalContent.html',
        controller: 'ModalInstanceCtrl',
        size: size,
        resolve: {
            items: function () {
                return $scope.items;
            }
        }
    });

    modalInstance.opened.then(function () {
        $scope.modalOpen = true;
    });

    // we want to update state whether the modal closed or was dismissed,
    // so use finally to handle both resolved and rejected promises.
    modalInstance.result.finally(function (selectedItem) {
        $scope.modalOpen = false;
    });
};

你想打电话给承诺,然后做你需要的任何事情..opened是模式打开.result时的承诺,是模态关闭时的承诺.所以使用这个想法,你将使用$scope.modalOpen你的布尔值.