如何在Selenium WebDriver中使用xPath来获取SVG元素？

Question

我正在OpenLayers使用Selenium WebDriver(Java版本)测试API .

我想测试一个使用OpenLayers.Control.ModifyFeature 的功能.我想点击绘制的特征(SVG),然后拖动并检查它们是否存在,可见或隐藏.

我画了一个多边形,我选择了它.见下图:

这些SVG元素的HTML在这里:

<svg id="OpenLayers_Layer_Vector_161_svgRoot" width="1235" height="495" viewBox="0 0 1235 495" style="display: block;">
    <g id="OpenLayers_Layer_Vector_161_root" transform="" style="visibility: visible;">
        <g id="OpenLayers_Layer_Vector_161_vroot">
            <path id="OpenLayers_Geometry_Polygon_200" d=" M 393.0000000000964,213.9999999999891 486.0000000003338,275.9999999997126 384.00000000036925,284.9999999994434 393.0000000000964,213.9999999999891 z" fill-rule="evenodd" fill="blue" fill-opacity="0.4" stroke="blue" stroke-opacity="1" stroke-width="2" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="pointer" />
            <circle id="OpenLayers_Geometry_Point_619" cx="439.50000000021464" cy="244.99999999985084" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_621" cx="435.00000000035106" cy="280.49999999958163" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_623" cx="388.50000000023283" cy="249.4999999997126" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_202" cx="393.0000000000964" cy="213.9999999999891" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_203" cx="486.0000000003338" cy="275.9999999997126" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_204" cx="384.00000000036925" cy="284.9999999994434" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
        </g>
        <g id="OpenLayers_Layer_Vector_161_troot" />
    </g>
</svg>

假设我想选择红点.

我这样做了:

String xpath = "//circle[contains(@id, 'OpenLayers_Geometry_Point') AND fill = '#990000']";
List<WebElement> vertices = driver.findElements(By.xpath(xpath));

但它总是返回一个空列表[].

我在这做错了什么？请问有人帮帮我吗？

非常感谢.

编辑1 - 功能:verticesAreVisible

在单击操作之前,我想获取元素并检查它们是否可见.我正在使用这个功能.

public static boolean verticesAreVisible(WebDriver driver, String xpath) {
    List<WebElement> list = driver.findElements(By.xpath(xpath));
    if (list.isEmpty()) {
        return false;
    }
    boolean visible = true;
    for (int i = 0; i < list.size(); i++) {
        visible = visible && list.get(i).isDisplayed();
    }
    return !verticesAreNotVisible(driver) && visible;
}

编辑2 - 纠正xPath

// This solution from Razib is valid if the SVG is on the root note
String xpath = "/*[name()='svg']/*[name()='circle']";
// I changed it so that any descendant is valid "//"
String xpath = "//*[name()='svg']//*[name()='circle']";
// Since I wanted only the red vertices, I added this
String xpath = "//*[name()='svg']//*[name()='circle' and @fill='#990000']";

Answer 1

可能是您需要使用Actions with name属性Xpath.在你的XPath中使用它 -

"/*[name()='svg']/*[name()='SVG OBJECT']"  

然后尝试以下代码段 -

WebElement svgObj = driver.findElement(By.xpath(XPATH));
Actions actionBuilder = new Actions(driver);
actionBuilder.click(svgObj).build().perform();

Answer 2

要定位红点，即具有包含OpenLayers_Geometry_Pointfill="#990000"的属性和id属性的元素，您可以使用以下定位器策略之一：

• 使用xpath：

  //*[name()='svg']/*[name()='g']/*[name()='g']//*[name()='circle' and contains(@fill, '990000')][starts-with(@id, 'OpenLayers_Geometry_Point')]
  

• 使用css 选择器：

  svg > g > g circle[fill$='990000'][id^='OpenLayers_Geometry_Point']
  

理想情况下，您需要引发WebDriverWait，并且visibilityOfAllElementsLocatedBy()可以使用以下任一定位器策略：

• 使用cssSelector：

  List<WebElement> vertices = new WebDriverWait(driver, 20).until(ExpectedConditions.visibilityOfAllElementsLocatedBy(By.cssSelector("svg > g > g circle[fill$='990000'][id^='OpenLayers_Geometry_Point']")));
  

• 使用xpath：

  List<WebElement> vertices = new WebDriverWait(driver, 20).until(ExpectedConditions.visibilityOfAllElementsLocatedBy(By.xpath("//*[name()='svg']/*[name()='g']/*[name()='g']//*[name()='circle' and contains(@fill, '990000')][starts-with(@id, 'OpenLayers_Geometry_Point')]")));
  

参考

您可以在以下位置找到一些相关细节的讨论：

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