Abe*_*ler 5 sql sql-server common-table-expression sql-server-2008
说我有下表:
id|myId|Name
-------------
1 | 3 |Bob
2 | 3 |Chet
3 | 3 |Dave
4 | 4 |Jim
5 | 4 |Jose
-------------
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是否可以使用递归CTE生成以下输出:
3 | Bob, Chet, Date
4 | Jim, Jose
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我已经玩过一些但却无法让它发挥作用.我会用更好的技术做得更好吗?
我不推荐这个,但我设法解决了这个问题.
表:
CREATE TABLE [dbo].[names](
[id] [int] NULL,
[myId] [int] NULL,
[name] [char](25) NULL
) ON [PRIMARY]
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数据:
INSERT INTO names values (1,3,'Bob')
INSERT INTO names values 2,3,'Chet')
INSERT INTO names values 3,3,'Dave')
INSERT INTO names values 4,4,'Jim')
INSERT INTO names values 5,4,'Jose')
INSERT INTO names values 6,5,'Nick')
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查询:
WITH CTE (id, myId, Name, NameCount)
AS (SELECT id,
myId,
Cast(Name AS VARCHAR(225)) Name,
1 NameCount
FROM (SELECT Row_number() OVER (PARTITION BY myId ORDER BY myId) AS id,
myId,
Name
FROM names) e
WHERE id = 1
UNION ALL
SELECT e1.id,
e1.myId,
Cast(Rtrim(CTE.Name) + ',' + e1.Name AS VARCHAR(225)) AS Name,
CTE.NameCount + 1 NameCount
FROM CTE
INNER JOIN (SELECT Row_number() OVER (PARTITION BY myId ORDER BY myId) AS id,
myId,
Name
FROM names) e1
ON e1.id = CTE.id + 1
AND e1.myId = CTE.myId)
SELECT myID,
Name
FROM (SELECT myID,
Name,
(Row_number() OVER (PARTITION BY myId ORDER BY namecount DESC)) AS id
FROM CTE) AS p
WHERE id = 1
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根据要求,这是XML方法:
SELECT myId,
STUFF((SELECT ',' + rtrim(convert(char(50),Name))
FROM namestable b
WHERE a.myId = b.myId
FOR XML PATH('')),1,1,'') Names
FROM namestable a
GROUP BY myId
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