我有以下功能来获得以下输出
22
4444
666666
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相反,我得到
'22\n4444\n666666\n88888888\n'
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我哪里出错了?
def EvenLadder(n):
...: solution = ''
...: if n <= 1:
...: return solution
...: elif n%2 ==0:
...: for i in range(2,n+1,2):
...: solution += (str(i)*i)+"\n"
...: else:
...: n = n - 1
...: for i in range(2,n+1,2):
...: solution += (str(i)*i)+"\n"
...: return solution
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'22\n4444\n666666\n88888888\n'是预期结果的正确字符串表示形式。为了实际处理换行符,您需要打印它:
print EvenLadder(6)
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