如何显示谷歌自定义搜索结果的下一页？

Question

我知道SOF有很多类似的问题,但我没有找到对我有用的东西.根据Google Custom Search文档,&start参数:

The start parameter uses a zero-based index, meaning the first result is 0, the second result is 1 and so forth.

The start parameter works in conjunction with the num parameter to determine which search results to return. 

我尝试从零发送,但应用程序崩溃.在这次尝试中我尝试发送:

为1页: &num=10&start=1

2页: &num=10&start=11

但它仍然要求1页.&start参数始终被忽略

我正在写一个Android应用程序,它进行图像搜索,在向下滚动它应该在下一页(下10个图像),在android 它总是返回1页有10个图像,我在浏览器中测试请求,withount &num参数,它的工作原理.在Android上,似乎在第一页加载后,参数&start和&num被忽略.

我使用robospice与改造相结合,我无法弄清楚如何获取请求字符串,也许我做错了什么

这是我的界面:

 public static final String BASE_URL = "https://www.googleapis.com/customsearch";
public static final String API_KEY = "AIzaSyCCuxxVLzm2sZP-adhRNYKeSck1mMMgsAM";
public static final String CUSTOM_SEARCH_ID = "001734592082236324715:sob9rqk49yg";
public static final String SEARCH_TYPE_IMAGE = "image";
static final String FILTER = "&fields=queries(nextPage(startIndex,count),request(startIndex,count)),searchInformation(totalResults),items(title,link,displayLink,mime," +
        "image)";
static final String QUERY = "/v1?key="+API_KEY+
                            "&cx="+CUSTOM_SEARCH_ID+
                            "&searchType="+SEARCH_TYPE_IMAGE+FILTER+"&num=10";

@GET(QUERY)
public GoogleSearchResponse search(@Query("q") String query,
                                   @Query("start") long startIndex);

SpiceRequest

public class SampleRetrofitSpiceRequest extends RetrofitSpiceRequest<GoogleSearchResponse,GoogleSearchInterface> {

String query;
long startIndex;

public SampleRetrofitSpiceRequest(String query, long startIndex) {
    super(GoogleSearchResponse.class, GoogleSearchInterface.class);
    this.query = query;
    this.startIndex = startIndex;
}
@Override
public GoogleSearchResponse loadDataFromNetwork() throws Exception {
    return getService().search(query,startIndex);
}}

SpiceService

public class SampleRetrofitSpiceService extends RetrofitGsonSpiceService {
@Override
public void onCreate() {
    super.onCreate();
    addRetrofitInterface(GoogleSearchInterface.class);
}

@Override
protected String getServerUrl() {
    return GoogleSearchInterface.BASE_URL;
}}

现在我如何获取请求获取第一个结果页面,在页面参数I发送1,进入第二页我发送11:

 public void sendRequest(String query,int page){
    searchQuery = query;
    request = new SampleRetrofitSpiceRequest(query, page);

    spiceManager.execute(request, query, DurationInMillis.ONE_WEEK, new RequestImageListener());
    request=null;
}

这里是响应监听器,nextPage是下一页的一些数字:

 private class RequestImageListener implements RequestListener<GoogleSearchResponse> {
    @Override
    public void onRequestFailure(SpiceException spiceException) {
        Toast.makeText(context, "failure", Toast.LENGTH_SHORT).show();
    }
    @Override
    public void onRequestSuccess(GoogleSearchResponse s) {
        Toast.makeText(context,"success",Toast.LENGTH_SHORT).show();
        nextPage = s.queries.getNextPage().startIndex;
        Log.d("myTag","nextPage "+currentPage);
        updateSearchResults(s.items);
    }
}

UPDATE 日志显示自定义SpiceRequest不会发出新请求,即使我创建它的新实例也是如此.

Answer 1

似乎可以使用“start=PUT_NUMBER_HERE”URL 选项来获取更多结果。

Number 是结果的序号，从 1 开始。

示例： https: //www.googleapis.com/customsearch/v1? q=searchtermhere&cx=asdfasdfasdf&key=adfasfdafasfd&start=11