Bob*_*Bob 1 python statistics pandas
我有一个这样的DataFrame
a = pd.DataFrame(a.random.random(5, 10), columns=['col1','col2','col3','col4','col5'])
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我想col4根据一组阈值来量化一个特定的列(例如,对应的输出可以是从0到级别数的整数)。是否有API?
大多数熊猫对象与numpy函数兼容。我会使用numpy.digitize:
import pandas as pd
a = pd.DataFrame(pd.np.random.random((5, 5)), columns=['col1','col2','col3','col4','col5'])
# col1 col2 col3 col4 col5
#0 0.523311 0.266401 0.939214 0.487241 0.582323
#1 0.274436 0.761046 0.155482 0.630622 0.044595
#2 0.505696 0.953183 0.643918 0.894726 0.466916
#3 0.281888 0.621781 0.900743 0.339057 0.427644
#4 0.927478 0.442643 0.541234 0.450761 0.191215
pd.np.digitize( a.col4, bins = [0.3,0.6,0.9 ] )
#array([1, 2, 2, 1, 1])
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也许qcut()是您要寻找的。简短答案:
df['quantized'] = pd.qcut(df['col4'], 5, labels=False )
更长的解释:
>>> import pandas as pd
>>> import numpy as np
>>> df = pd.DataFrame(np.random.randn(10, 5), columns=['col1','col2','col3','col4','col5'])
>>> df
col1 col2 col3 col4 col5
0 0.502017 0.290167 0.483311 1.755979 -0.866204
1 0.374881 -1.372040 -0.533093 1.559528 -1.835466
2 -0.110025 -1.071334 -0.474367 -0.250456 0.428927
3 -2.070885 0.095878 -3.133244 -1.295787 0.436325
4 -0.974993 0.591984 -0.839131 -0.949721 -1.130265
5 -0.383469 0.453937 -0.266297 -1.077004 0.123262
6 -2.548547 0.424707 -0.955433 1.147909 -0.249138
7 1.056661 0.949915 -0.234331 -0.146116 0.552332
8 0.029098 -1.016712 -1.252748 -0.216355 0.458309
9 0.262807 0.029040 -0.843372 0.492120 0.128395
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您可以pd.qcut()用来获取相应的范围。
>>> q = pd.qcut(df['col4'], 5)
>>> q
0 (1.23, 1.756]
1 (1.23, 1.756]
2 (-0.975, -0.23]
3 [-1.296, -0.975]
4 (-0.975, -0.23]
5 [-1.296, -0.975]
6 (0.109, 1.23]
7 (-0.23, 0.109]
8 (-0.23, 0.109]
9 (0.109, 1.23]
Name: col4, dtype: category
Categories (5, object): [[-1.296, -0.975] < (-0.975, -0.23] < (-0.23, 0.109] < (0.109, 1.23] < (1.23, 1.756]]
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您可以设置参数labels=False以获取整数表示形式
>>> q = pd.qcut(df['col4'], 5, labels=False)
>>> q
0 4
1 4
2 1
3 0
4 1
5 0
6 3
7 2
8 2
9 3
dtype: int64
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