如何量化熊猫中的数据?

Bob*_*Bob 1 python statistics pandas

我有一个这样的DataFrame

a = pd.DataFrame(a.random.random(5, 10), columns=['col1','col2','col3','col4','col5'])
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我想col4根据一组阈值来量化一个特定的列(例如,对应的输出可以是从0到级别数的整数)。是否有API?

der*_*men 5

大多数熊猫对象与numpy函数兼容。我会使用numpy.digitize

import pandas as pd

a = pd.DataFrame(pd.np.random.random((5, 5)), columns=['col1','col2','col3','col4','col5'])
#       col1      col2      col3      col4      col5
#0  0.523311  0.266401  0.939214  0.487241  0.582323
#1  0.274436  0.761046  0.155482  0.630622  0.044595
#2  0.505696  0.953183  0.643918  0.894726  0.466916
#3  0.281888  0.621781  0.900743  0.339057  0.427644
#4  0.927478  0.442643  0.541234  0.450761  0.191215

pd.np.digitize( a.col4, bins = [0.3,0.6,0.9 ]  )
#array([1, 2, 2, 1, 1])
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cch*_*chi 5

也许qcut()是您要寻找的。简短答案:

df['quantized'] = pd.qcut(df['col4'], 5, labels=False )

更长的解释:

>>> import pandas as pd
>>> import numpy as np
>>> df = pd.DataFrame(np.random.randn(10, 5), columns=['col1','col2','col3','col4','col5'])
>>> df
       col1      col2      col3      col4      col5
0  0.502017  0.290167  0.483311  1.755979 -0.866204
1  0.374881 -1.372040 -0.533093  1.559528 -1.835466
2 -0.110025 -1.071334 -0.474367 -0.250456  0.428927
3 -2.070885  0.095878 -3.133244 -1.295787  0.436325
4 -0.974993  0.591984 -0.839131 -0.949721 -1.130265
5 -0.383469  0.453937 -0.266297 -1.077004  0.123262
6 -2.548547  0.424707 -0.955433  1.147909 -0.249138
7  1.056661  0.949915 -0.234331 -0.146116  0.552332
8  0.029098 -1.016712 -1.252748 -0.216355  0.458309
9  0.262807  0.029040 -0.843372  0.492120  0.128395
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您可以pd.qcut()用来获取相应的范围。

>>> q = pd.qcut(df['col4'], 5)
>>> q
0       (1.23, 1.756]
1       (1.23, 1.756]
2     (-0.975, -0.23]
3    [-1.296, -0.975]
4     (-0.975, -0.23]
5    [-1.296, -0.975]
6       (0.109, 1.23]
7      (-0.23, 0.109]
8      (-0.23, 0.109]
9       (0.109, 1.23]
Name: col4, dtype: category
Categories (5, object): [[-1.296, -0.975] < (-0.975, -0.23] < (-0.23, 0.109] < (0.109, 1.23] < (1.23, 1.756]]
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您可以设置参数labels=False以获取整数表示形式

>>> q = pd.qcut(df['col4'], 5, labels=False)
>>> q
0    4
1    4
2    1
3    0
4    1
5    0
6    3
7    2
8    2
9    3
dtype: int64
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