在另一个ng-repeat中使用ng-repeat

Question

我正在开发一个页面,我需要显示一些ng-repeat包含频道信息的框(使用)以及它将在何处显示(哪些是城市).

我面临的问题是当我重复第二个问题时ng-repeat:

<table class="table table-condensed" ng-init="nitsCh = [objsCh[$index].nit]">

这应该得到第一个ng-repeat的$ index并创建一个新的数组,其中显示了通道的位置.它确实如此.但是,当我使用此数组应用第二个ng-repeat时,它无法正常工作.

说我的html看起来像这样(PS:我需要使用索引值而不是objCh.name因为我将这些框放入列中)

<div class="box box-solid box-default" ng-repeat="(indexO, objCh) in objsCh track by indexO" ng-if="indexO%4==0  && indexO<=10">
  <div class="box-header"> 
    <div class="pull-left"> 
      <img src="dist/img/channels/{{ objsCh[indexO].pic }}" data-toggle="tooltip" title="" data-original-title="Alterar logo do canal"> 
      <h3 class="box-title">{{ objsCh[(indexO)].name }}</h3> 
    </div> 
    <div class="box-tools pull-right"> 
      <button class="btn btn-box-tool" data-toggle="tooltip" title="" data-original-title="Adicionar ou Remover NIT"><i class="fa fa-plus"></i></button> 
    </div> 
  </div> 
  <div class="box-body"> 
    <table class="table table-condensed" ng-init="nitsCh = [objsCh[indexO].nit]"> 
      <tbody> 
        <tr> 
          <th style="width: 10px">#</th> 
          <th>Nit</th> 
        </tr> 
        <tr ng-repeat="(indexN,nitCh) in nitsCh track by indexN"> 
          <td>{{ objsCh[(indexO + 1)].nit[indexN].num }}</td>
          <td>{{ objsCh[(indexO + 1)].nit[indexN].name }}</td>
        </tr> 
      </tbody>
    </table> 
  </div> 
</div>

JS文件如下所示:

var app = angular.module('appApp', []);
app.controller('ctrlApp', function($scope, $http) {

    var url = "includes/exibChNit.php";

    $http.get(url).success(function(response) {
        all = response;
        $scope.objsCh = all.channels;
    });
});

而json文件(php创建)看起来像这样:

{
    "channels": [{
        "id": "1",
        "sid": "1",
        "name": "Channel",
        "pic": "channel.jpg",
        "crc32": "A1g423423B2",
        "special": "0",
        "url": "",
        "key": "",
        "type": "",
        "city": [{
            "num": "1",
            "name": "S?o Paulo"
        }, {
            "num": "2",
            "name": "Rio de Janeiro"
        }]
    }, {
        "id": "2",
        "sid": "2",
        "name": "CHannel 1",
        "pic": "channel.jpg",
        "crc32": "A1F5534234B2",
        "special": "0",
        "url": "",
        "key": "",
        "type": "",
        "city": [{
            "num": "1",
            "name": "S?o Paulo"
        }, {
            "num": "2",
            "name": "Rio de Janeiro"
        }]
    }]
}

当我尝试这个它工作:

<table class="table table-condensed" ng-init="nitsCh = [objsCh[($parent.$index + 1)].nit]">

但我不能这样做,因为json节点将是动态的.

提前致谢!

Answer 1

ng-repeat创造属于自己的$scope.

因此,对于内部ng-repeats,您可以访问$parent.$index,其中$parent是当前重复块的父作用域.

例如:

<ul ng-repeat="section in sections">
  <li>
      {{section.name}}
  </li>
  <ul>
    <li ng-click="loadFromMenu($parent.$index)" ng-repeat="tutorial in section.tutorials">
          {{tutorial.name}}
    </li>
  </ul>
</ul>

Plunkr http://plnkr.co/edit/hOfAldNevxKzZQlxFfBn?p=preview

(从这个答案中简化,在嵌套的ng-repeat中传递2 $索引值)