IMO,我认为epub是一种zip。因此,我尝试以某种方式解压缩。
public class Main {
public static void main(String argv[ ]) {
final int BUFFER = 2048;
try {
BufferedOutputStream dest = null;
FileInputStream fis = new FileInputStream("/Users/yelinaung/Documents/unzip/epub/doyle.epub");
ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while ((entry = zis.getNextEntry()) != null) {
System.out.println("Extracting: " + entry);
int count;
byte data[] = new byte[BUFFER];
// write the files to the disk
FileOutputStream fos = new FileOutputStream("/Users/yelinaung/Documents/unzip/xml/");
dest = new BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))
!= -1) {
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
zis.close();
} catch ( IOException e) {
e.printStackTrace();
}
}
}
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我收到了以下错误..
java.io.FileNotFoundException: /Users/yelinaung/Documents/unzip/xml (No such file or directory)
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尽管我以这种方式创建了一个文件夹..并且
我解压缩epub的方法是正确的方法吗?.. 纠正我
我有答案..我还没有检查必须提取的对象是否为folder。
我已经以这种方式纠正了。
public static void main(String[] args) throws IOException {
ZipFile zipFile = new ZipFile("/Users/yelinaung/Desktop/unzip/epub/doyle.epub");
String path = "/Users/yelinaung/Desktop/unzip/xml/";
Enumeration files = zipFile.entries();
while (files.hasMoreElements()) {
ZipEntry entry = (ZipEntry) files.nextElement();
if (entry.isDirectory()) {
File file = new File(path + entry.getName());
file.mkdir();
System.out.println("Create dir " + entry.getName());
} else {
File f = new File(path + entry.getName());
FileOutputStream fos = new FileOutputStream(f);
InputStream is = zipFile.getInputStream(entry);
byte[] buffer = new byte[1024];
int bytesRead = 0;
while ((bytesRead = is.read(buffer)) != -1) {
fos.write(buffer, 0, bytesRead);
}
fos.close();
System.out.println("Create File " + entry.getName());
}
}
}
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然后,得到它。