RuntimeError:在应用程序上下文之外工作

gur*_*uri 38 python mysql werkzeug flask flask-restful

app.py

from flask import Flask, render_template, request,jsonify,json,g
import mysql.connector

app = Flask(__name__)
**class TestMySQL():**
  @app.before_request
  def before_request():
    try:
       g.db = mysql.connector.connect(user='root', password='root', database='mysql')
    except mysql.connector.errors.Error as err:
      resp = jsonify({'status': 500, 'error': "Error:{}".format(err)})
      resp.status_code = 500
      return resp
@app.route('/')
def input_info(self):
    try:     
        cursor = g.db.cursor()
        cursor.execute ('CREATE TABLE IF NOT EXISTS testmysql (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY, name VARCHAR(40) NOT NULL, \
                 email VARCHAR(40) NOT NULL UNIQUE)')
        cursor.close()
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test.py

from app import *
class Test(unittest.TestCase):         
 def test_connection1(self):  
   with patch('__main__.mysql.connector.connect') as  mock_mysql_connector_connect:
   object=TestMySQL()
   object.before_request()  """Runtime error on calling this"  
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我正在将app导入test.py进行单元测试.在test.py中调用' before_request '函数时,它会抛出RuntimeError:在应用程序上下文之外工作同样在调用' input_info() '时发生

bre*_*s10 66

Flask有一个Application Context,看起来你需要做类似的事情:

def test_connection(self):
    with app.app_context():
        #test code
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您也可以将app.app_context()调用推送到测试设置方法中.希望这可以帮助.

  • 我因为使用​​“jsonify”而得到这个。简单的 JSON 转换需要应用程序“在上下文中”运行,这确实很糟糕。 (8认同)

小智 23

app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///todo.db'
app.config['SQLALCHEMY_TRACK_MODIFICATIONS'] = False
db = SQLAlchemy(app)

app.app_context().push()

Run in terminal
    >python
    >>>from app import app
    >>>from app import db
    >>>db.create_all()

Now it should work
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Pad*_*ton 6

当我在使用 时遇到类似的问题时,我遵循了@brenns10的答案pytest

我按照将其放入测试设置的建议,这有效:

import pytest
from src.app import app


@pytest.fixture
def app_context():
    with app.app_context():
        yield


def some_test(app_context):
    # <test code that needs the app context>
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