asi*_*swt 8 sql oracle data-warehouse aggregate-functions oracle11g
假设我有2个表T1,T2如下所示
T1:
bag_id bag_type capacity
------|--------|--------
1 A 500
2 A 300
3 A 100
4 B 200
5 B 100
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T2:
item_type item_amount
---------|-----------
A 850
B 300
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表中的每个记录T1代表一个包及其容量,这里我有5个包.我想编写一个SQL,将表中的项目分配T2到具有相同类型的每个包中,即结果应该是这样的
bag_id bag_type capacity allocated_amount
------|--------|--------|----------------
1 A 500 500
2 A 300 300
3 A 100 50
4 B 200 200
5 B 100 100
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因此,我发现了一些聚合函数,我们称之为allocate()可以产生allocated_amount如上所述的列.我猜想,如果存在,它可能会像这样使用
select
t1.bag_id,
t1.bag_type,
t1.capacity,
allocate(t2.item_amount, t1.capacity)
over (partition by t1.bag_type order by t1.capacity desc) as allocatd_amount
from t1, t2
where t2.item_type = t1.bag_type
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我目前的解决方案是使用临时表和PL/SQL循环进行计算,但我希望我能用一个简单的SQL来完成.
您正在寻找累积总和。像这样的东西:
select t1.*,
(case when cumecap <= t2.item_amount
then t1.capacity
when cumecap - t1.capacity <= t2.item_amount
then t2.item_amount - (cumecap - t1.capacity)
else 0
end) as allocated_capacity
from (select t1.*,
sum(t1.capacity) over (partition by bag_type order by bag_id) as cumecap
from t1
) t1 join
t2
on t1.bag_type = t2.item_type;
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