如何使用Swift检查iOS设备是否被锁定/解锁？

Question

如何使用Swift检测锁定/解锁的iOS设备(如Android中的SCRENON/SCREENOFF)

Answer 1

我使用以下来创建相同的想法.

您需要使用桥接器将目标c代码用于swift.

这是用于在Objective c到Swift之间创建桥梁的Link.

完成后,您可以添加以下.h文件yourproject-Bridging-Header.file添加yourcontroller.h

然后将NotificationCenter.framework添加到项目中.

进入你的CustomObject.m

#import "notify.h"

-(void)registerAppforDetectLockState {

    int notify_token;
    notify_register_dispatch("com.apple.springboard.lockstate", &notify_token,dispatch_get_main_queue(), ^(int token) {

        uint64_t state = UINT64_MAX;
        notify_get_state(token, &state);

        if(state == 0) {
            NSLog(@"unlock device");
        } else {
            NSLog(@"lock device");
        }

        NSLog(@"com.apple.springboard.lockstate = %llu", state);
        UILocalNotification *notification = [[UILocalNotification alloc]init];
        notification.repeatInterval = NSCalendarUnitDay;
        [notification setAlertBody:@"Hello world!! I come becoz you lock/unlock your device :)"];
        notification.alertAction = @"View";
        notification.alertAction = @"Yes";
        [notification setFireDate:[NSDate dateWithTimeIntervalSinceNow:1]];
        notification.soundName = UILocalNotificationDefaultSoundName;
        [notification setTimeZone:[NSTimeZone  defaultTimeZone]];

        [[UIApplication sharedApplication] presentLocalNotificationNow:notification];

    });
}

然后是CustomObject.h

-(void)registerAppforDetectLockState;

现在进入swift代码,您可以直接使用此方法.

var instanceOfCustomObject: LockViewController = LockViewController()
instanceOfCustomObject.registerAppforDetectLockState();

愿这很有帮助.