用不同的值替换长字符串的部分

Question

我有一个像下面的字符串;

String textToShow = "Appplication [%ApplicationName%]: started at [%Date%][%Time%]"

当我需要在替换字符串之间[%和%]不同的价值观.

我确实喜欢下面,但它只适用于第一个,即"ApplicationName".

private String getTextVariableName(String stringToShow) {
    if (stringToShow.contains("[%") && stringToShow.contains("%]")) {
        String content[] = notificationText.split("%");
        return content[1];
    }
    return null;
}

private String replaceValue(String stringToShow, String dataToReplace) {
    return stringToShow.substring(0, stringToShow.indexOf("["))
            + dataToReplace
            + stringToShow.substring(stringToShow.indexOf("]") + 1, stringToShow.length());
}

public String processText(String stringToShow, String appname) {
    String variableName = getTextVariableName(stringToShow);
    String processedText = "Invalid";
    if (variableName != null) {
        switch (variableName.toLowerCase()) {

        case "applicationname":
            processedText = replaceValue(stringToShow, appname);
            break;

        case "datetime":
            LocalDateTime currentDateTime = LocalDateTime.now();
            String formattedCurrentDateTime = currentDateTime
                    .format(DateTimeFormatter
                            .ofPattern("yyyy-MM-dd HH:mm:ss"));
            processedText = replaceValue(stringToShow,
                    formattedCurrentDateTime);
            break;

        case "date":
            LocalDate currentDate = LocalDate.now();
            String formattedCurrentDate = currentDate
                    .format(DateTimeFormatter.ofPattern("yyyy-MM-dd"));
            processedText = replaceValue(stringToShow,
                    formattedCurrentDate);
            break;

        case "time":
            LocalTime currentTime = LocalTime.now();
            String formattedCurrentTime = currentTime
                    .format(DateTimeFormatter.ofPattern("HH:mm:ss"));
            processedText = replaceValue(notificationText,
                    formattedCurrentTime);
            break;

        default:
            processedText = "Invalid";
            break;
        }
    }
    return processedText;
}

如果有更多与此类似的部分出现,我怎样才能使它对整个字符串起作用而不进一步分裂呢？

有没有分裂的更好的方法？

注意:我从DataBase获取此字符串,因此我无法更改字符串.我只需要更换的部分[%,并%]根据字符串的名称.就像,如果它是一个日期,它必须被日期替换,依此类推.

Answer 1

关于什么:

String textToShow = "Appplication [%ApplicationName%]: started at [%Date%][%Time%]"
textToShow = textToShow.replace("[%ApplicationName%]","your new string here");
textToShow = textToShow.replace("[%Date%]","your new date here");
textToShow = textToShow.replace("[%Time%]","your new time here");

更直接,更容易,更少错误修剪