JPA/JPQL JOIN 子选择/子查询

Joa*_*idt 6 java jpa join subquery jpql

由于使用了 JPQL 不支持的子查询,我无法将一些简单的 SQL 语句转换为 JPQL。

有人可以给我一个提示,如何使用 JPQL 或 JPA2 Criteria API 实现相同的结果?

给定(简化的假数据以证明问题):

CREATE TABLE person (id integer, name text);
CREATE TABLE phone (id integer, person_id integer, type text, number text);

INSERT INTO person VALUES (1, "John");
INSERT INTO person VALUES (2, "Mike");
INSERT INTO person VALUES (3, "Paul");
INSERT INTO person VALUES (4, "Walter");

INSERT INTO phone VALUES (1, 1, "MOBILE", "+49-123-11111");
INSERT INTO phone VALUES (2, 1, "HOME"  , "+49-123-22222");
INSERT INTO phone VALUES (3, 2, "WORK"  , "+49-123-33333");
INSERT INTO phone VALUES (4, 4, "MOBILE", "+49-123-44444");

-- Select all from person and their mobile number if possible
-- This query has to be translated to JPQL

SELECT person.name, mobile.number FROM person LEFT JOIN (
  SELECT * FROM phone WHERE type = "MOBILE"
) AS mobile ON person.id = mobile.person_id;
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预期结果:

| name   | number        |
|--------|---------------|
| John   | +49-123-11111 |
| Mike   |               |
| Paul   |               |
| Walter | +49-123-44444 |
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爪哇:

class Person {
    String name;
    List<Phone> phones;
}

class Phone {
    String type;
    String number;
}
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JPQL(未按预期工作:-():

SELECT person.name, phone.number FROM Person person
    LEFT JOIN person.phones AS phone
    WHERE phone.type = "MOBILE"
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Dra*_*vic 2

SELECT person.name, phone.number 
   FROM Person AS person LEFT JOIN person.phones AS phone 
   ON phone.type = 'MOBILE'
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您还可以将ON关键字替换为 hibernate 特定的WITH

SELECT person.name, phone.number 
   FROM Person AS person LEFT JOIN person.phones AS phone 
   WITH phone.type = 'MOBILE'
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