Python:如何在两个列表中对元素进行乘法和求和(不使用库)?

die*_*gus 2 python list

我有两个包含数字列表的列表(m1和m2).我正在尝试进行元素乘法和求和,包括交叉乘积以获得最终列表(结果),如下所示:

m1 = [[1, 2, 3], [4, 5, 6]]
m2 = [[7, 9, 2], [8, 1, 3]]

[[1*7+2*9+3*2,1*8+2*1+3*3],[4*7+5*9+6*2,4*8+5*1+6*3]]

result = [[31,19],[85,55]]
Run Code Online (Sandbox Code Playgroud)

Kas*_*mvd 6

您可以使用python 内置函数和嵌套列表解析:

>>> [[sum(t*k for t,k in zip(i,j)) for j in m2] for i in m1]
[[31, 19], [85, 55]]
Run Code Online (Sandbox Code Playgroud)

您还可以使用itertools.product在子列表之间查找产品:

>>> from itertools import product
>>> [sum(t*k for t,k in zip(i,j)) for i,j in product(m1,m2)]
[31, 19, 85, 55]
Run Code Online (Sandbox Code Playgroud)


Hai*_* Vu 5

让我们把问题分解成更小的部分。在最低级别,我们有两个小列表:[1, 2, 3][7, 9, 2],并且想要将它们逐项相乘:

item1 = [1, 2, 3]
item2 = [7, 9, 2]
zip(item1, item2)                        # ==> [(1, 7), (2, 9), (3, 2)]
[x * y for x, y in zip(item1, item2)]    # ==> [7, 18, 6]
sum(x * y for x, y in zip(item1, item2)) # ==> 31
Run Code Online (Sandbox Code Playgroud)

现在,我们可以将其放在双循环中:

[[sum(x * y for x, y in zip(item1, item2)) for item2 in m2] for item1 in m1]
# ==> [[31, 19], [85, 55]]
Run Code Online (Sandbox Code Playgroud)