多维数组,删除键和值与另一个数组匹配的数组

Question

我想删除重复项,其中测量或altunit匹配另一个数组,但忽略它们是否为空.

Array
(
    [0] => Array
        (
            [id] => 2
            [altunit] => %
            [measurement] => 
        )

    [1] => Array
        (
            [id] => 3
            [altunit] => 
            [measurement] => 6
        )

    [2] => Array
        (
            [id] => 4
            [altunit] => %
            [measurement] => 
        )

    [3] => Array
        (
            [id] => 5
            [altunit] => 
            [measurement] => 6
        )

    [4] => Array
        (
            [id] => 6
            [altunit] => 
            [measurement] => 6
        )

)

变

Array
(
    [0] => Array
        (
            [id] => 2
            [altunit] => %
            [measurement] => 
        )

    [1] => Array
        (
            [id] => 3
            [altunit] => 
            [measurement] => 6
        )

)

我能想出的最好的是:

$test = array ( 0 => array ( 'id' => '2', 'altunit' => '%', 'measurement' => NULL, ), 1 => array ( 'id' => '3', 'altunit' => NULL, 'measurement' => '6', ), 2 => array ( 'id' => '4', 'altunit' => NULL, 'measurement' => '6', ), 3 => array ( 'id' => '5', 'altunit' => NULL, 'measurement' => '6', ), 4 => array ( 'id' => '6', 'altunit' => NULL, 'measurement' => '6', ), );

$num = [];
foreach($test as $k => $v) $num[] = $v['measurement'];

但这仅适用于测量,并删除id和altunit键.

Answer 1

嗯，为测量和 altunit 创建一个“已知值”数组，然后检查它是否存在于其余值中。

就像是：

$knowed_altunit=array();
$knowed_measurement=array();

foreach($test as $k=>$v){
  if(in_array($v['altunit'],$knowed_altunit) 
  || in_array($v['mesurement'],$knowed_measurement)){
    //if the value of altunit or measurement is already knowed then remove the entry from the array,
    unset($test[$k]);
  }else{
   //if it never been seen, add it so further entry can be checked agaisnt the knowed value
   $knowed_altunit[]=$v['altunit'];
   $knowed_measurement[]=$v['mesurement'];
  }
}

抱歉，如果有任何拼写错误，但 Thins 可能会帮助您解决问题。