为什么提交表单上的按钮不起作用?

Ber*_*ard -1 html javascript css forms

我已经下载了一个样本表格,它是这样的:

  <form id="login-user"  method="post" accept-charset="utf-8" action="/home.html" class="simform">
    <div class="sminputs">
      <div class="input full">
        <label class="string optional" for="user-name">Email*</label>
        <input class="string optional" maxlength="255" id="user-email" placeholder="Email" type="email" size="50" />
      </div>
    </div>
    <div class="sminputs">
      <div class="input full">
        <label class="string optional" for="user-pw">Password *</label>
        <input class="string optional" maxlength="255" id="user-pw" placeholder="Password" type="password" size="50" />
                                <span class="hide-password">Show</span>
      </div>
    </div>

    <div class="simform__actions">
      <input class="sumbit" name="commit" type="sumbit" value = "Log in"/>
      <span class="simform__actions-sidetext"><a class="special" role="link" href="#">Forgot your password?<br>Click here</a></span>
    </div> 
  </form>
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当我按下提交按钮时它不起作用,它会点击按钮上的文字!但是,当我改变这一行

<input class="sumbit" name="commit" type="sumbit" value = "Log in"/>
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<button class="sumbit" name="commit" type="sumbit" value = "Log in"/>
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它正在工作,但我的CSS设计将会改变.

我的另一个问题是,我想知道CSS文件是否会影响html页面的功能.我认为这只会影响设计和外观.它是否影响上述功能?

编辑

这是我的javascript

$("#login-user").submit(function(event){
        event.preventDefault();
        alert("Here");
        var name = $("#user-email").val();
        var pass = $("#user-pw").val();

        Parse.User.logIn(name,pass,{
            success: function(user){
                checkLogin();
                alert("Thanks for login");
                window.location.href = "/home.html";
        }, error : function(user, error){
            console.log("Login Error : " + error.message);

        }
    });
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Sam*_*ong 5

我认为这是正确的.

 <button class="sumbit" name="commit" type="submit" value = "">
  Log in
 </button>
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type="sumbit"错了.