如何合并具有相同数据的连续subArrays？

Question

我有这个数组:

$opening_hours = array(
  'Monday' => array('09:00', '17:00'),
  'Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'), 
  'Thursday' => array('09:00', '17:00'),
  'Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00'),
  'Sunday' => array('Closed'),
);

我需要以某种方式将这些开放时间合并到数组中,这应该是这样的:

$merged_opening_hours = array(
  'Monday - Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'),
  'Thursday - Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00');
  'Sunday' => array('Closed'),
);

有任何想法吗？

Answer 1

这应该适合你:

所以基本上你只需循环遍历整个数组并检查下一个元素是否仍然设置并且当前数组与下一个元素相同(这意味着它们具有相同的小时数).如果是,则执行此操作直到while循环返回false.这是什么代码:

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

然后,如果您有多个条目,则可以创建从一个到另一天的范围.这是什么代码:

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

如果您只有相同时间的1天,则只需将其添加到结果数组中.这是什么代码:

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

并且根据同一时间你跳过下一个数组元素的天数.这是什么代码:

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

完整代码:

<?php

    $opening_hours = [
            "Monday" => ["09:00", "17:00"],
            "Tuesday" => ["09:00", "17:00"],
            "Wednesday" => ["08:00", "13:00"], 
            "Thursday" => ["09:00", "17:00"],
            "Friday" => ["09:00", "17:00"],
            "Saturday" => ["10:00", "16:00"],
            "Sunday" => ["Closed"],
        ];


    $amountOfDays = count($opening_hours);
    $arrayKeys = array_keys($opening_hours);

    for($dayCount = 0; $dayCount < $amountOfDays; $dayCount++) {
        $DayAmountOfConsecutiveSameHours = 1;
        while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
            $DayAmountOfConsecutiveSameHours++;

        if($DayAmountOfConsecutiveSameHours > 1)
            $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];
        else
            $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

        $dayCount += ($DayAmountOfConsecutiveSameHours - 1);
    }

    print_r($result);

?>

输出:

Array
(
    [Monday - Tuesday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Wednesday] => Array
        (
            [0] => 08:00
            [1] => 13:00
        )

    [Thursday - Friday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Saturday] => Array
        (
            [0] => 10:00
            [1] => 16:00
        )

    [Sunday] => Array
        (
            [0] => Closed
        )

)

Demo