Ris*_*ain 16 html javascript php forms checkbox
如果选中复选框数组中的复选框,如何提交值1,如果未选中则提交0?我试过这个,但没有运气.我正在尝试在提交表单时在php数组中获取此数组.请帮忙!
<input id = 'testName0' type = 'checkbox' name = 'check[0]' value = '1' checked>
<input id='testNameHidden0' type='hidden' value='0' name='check[0]'>
<input id = 'testName1' type = 'checkbox' name='check[1]' value = '1' unchekced>
<input id='testNameHidden1' type='hidden' value='0' name='check[1]'>
<input type = 'submit' value = 'Save Changes'>
>
<script>
if(document.getElementById('testName0').checked){
document.getElementById('testNameHidden0').disabled = true;
}
</script>
<script>
if(document.getElementById('testName1').checked){
document.getElementById('testNameHidden1').disabled = true;
}
</script>
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Jun*_*bie 43
最简单的一个,不需要javascript,只需在复选框之前输入一个隐藏的输入:
<input type="hidden" name="check[0]" value="0" />
<input type="checkbox" name="check[0]" value="1" />
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输入需要具有相同的名称.如果选中该复选框,则将提交值1,否则从隐藏输入中返回值0.
你的案例javascript解决方案,不需要隐藏的输入:
<script type="text/javascript">
// when page is ready
$(document).ready(function() {
// on form submit
$("#form").on('submit', function() {
// to each unchecked checkbox
$(this + 'input[type=checkbox]:not(:checked)').each(function () {
// set value 0 and check it
$(this).attr('checked', true).val(0);
});
})
})
</script>
<form method="post" id="form">
<input type="checkbox" name="check[0]" value="1" />
<input type="checkbox" name="check[1]" value="1" />
<input type="submit" value="Save Changes" />
</form>
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PHP解决方案,无需隐藏输入:
<?php
// if data is posted, set value to 1, else to 0
$check_0 = isset($_POST['check'][0]) ? 1 : 0;
$check_1 = isset($_POST['check'][1]) ? 1 : 0;
?>
<form method="post">
<input type="checkbox" name="check[0]" value="1" />
<input type="checkbox" name="check[1]" value="1" />
<input type="submit" value="Save Changes" />
</form>
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