XStream - Root作为对象的集合

Question

我正在使用类似于此的XML有效负载(有关更全面的示例,请查看:http://api.shopify.com/product.html).

<products type="array">
   <product>
      ...
   </product>
   <product>
      ...
   </product>
</products>

现在我的代码确实有效,但它做的事情似乎真的"错误" - 即它将"产品"与List.class相关联.所以相关代码如下所示:

    xstream.alias( "products", List.class );
    xstream.alias( "product", ShopifyProduct.class );

这很好,除非我转到使用该xstream实例外部化任何对象时,它总是使用"产品",这不是我想要的.

我想要能够将通用集合映射到标签:

xstream.alias( "products", ( List<ShopifyProduct> ).class ); // way too easy 

或者让以下snipet工作,但目前还没有:

    ClassAliasingMapper mapper = new ClassAliasingMapper( xstream.getMapper( ) );
    mapper.addClassAlias( "product", ShopifyProduct.class );
    xstream.registerLocalConverter( ShopifyProductResponse.class, "products", new CollectionConverter( mapper ) );

我创建了ShopifyProductResponse类来尝试包装ShopifyProduct,但它没有任何告诉我:

com.thoughtworks.xstream.mapper.CannotResolveClassException:products:com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:68)中的产品,位于com.thoughtworks.xstream.mapper.MapperWrapper.realClass(MapperWrapper.java:38) )

如果我添加:

xstream.alias( "products", List.class );

然后它消失了...所以在我看来mapperwrapper没有抓住这里 - 可能是因为它寻找ShopifyProductResponse对象并找到一个List而不是 - 我真的不知道.

Answer 1

如果我理解正确,这就是你要找的. ShoppifyProductResponse.java

public class ShoppifyProductResponse {

private List<ShoppifyProduct> product;

/**
 * @return the products
 */
public List<ShoppifyProduct> getProducts() {
    return product;
}

/**
 * @param products
 *            the products to set
 */
public void setProducts(List<ShoppifyProduct> products) {
    this.product = products;
}

}

还有一个转换器.UnMarshalling可能看起来像这样.

public Object unmarshal(HierarchicalStreamReader reader, UnmarshallingContext context) {
    /**
     * Tune the code further..
     */
    ShoppifyProductResponse products = new ShoppifyProductResponse();
    List<ShoppifyProduct> lst = new ArrayList<ShoppifyProduct>();
    while (reader.hasMoreChildren()) {
        reader.moveDown();
        ShoppifyProduct thisProduct = (ShoppifyProduct) context.convertAnother(products,
                ShoppifyProduct.class);
        lst.add(thisProduct);
        reader.moveUp();
    }
    products.setProducts(lst);
    return products;
}

你可以注册为,

    XStream stream = new XStream();
    stream.alias("products", ShoppifyProductResponse.class);
    stream.registerConverter(new ShoppifyConverter());
    stream.alias("product", ShoppifyProduct.class);

我试过这个,它的效果非常好.试一试,让我知道.