Mos*_*ted 6 python asynchronous coroutine python-3.x
我有一堆协程在做一些工作
@asyncio.coroutine
def do_work():
global COUNTER
result = ...
if result.status == 'OK':
COUNTER += 1
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和另一个
COUNTER = 0
@asyncio.coroutine
def display_status():
while True:
print(COUNTER)
yield from asyncio.sleep(1)
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其中必须显示有多少协程完成了它们的工作。如何正确执行此任务?以下解决方案不起作用
@asyncio.coroutine
def spawn_jobs():
coros = []
for i in range(10):
coros.append(asyncio.Task(do_work()))
yield from asyncio.gather(*coros)
if __name__ == '__main__':
loop = asyncio.get_event_loop()
loop.create_task(display_status())
loop.run_until_complete(spawn_jobs())
loop.close()
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我希望无论 do_work() 协程做什么,计数器都会每秒打印到控制台。但我只有两个输出:0 和几秒钟后重复 10。
但我只有两个输出:0 和几秒钟后重复 10。
我无法重现它。如果我使用:
import asyncio
import random
@asyncio.coroutine
def do_work():
global COUNTER
yield from asyncio.sleep(random.randint(1, 5))
COUNTER += 1
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我得到这样的输出:
0
0
4
6
8
Task was destroyed but it is pending!
task: <Task pending coro=<display_status() running at most_wanted.py:16> wait_for=<Future pending cb=[Task._wakeup()] created at ../Lib/asyncio/tasks.py:490> created at most_wanted.py:27>
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无限循环在最后display_status()
导致警告。避免警告;当批处理中的所有任务完成时退出循环:
#!/usr/bin/env python3
import asyncio
import random
from contextlib import closing
from itertools import cycle
class Batch:
def __init__(self, n):
self.total = n
self.done = 0
async def run(self):
await asyncio.wait([batch.do_work() for _ in range(batch.total)])
def running(self):
return self.done < self.total
async def do_work(self):
await asyncio.sleep(random.randint(1, 5)) # do some work here
self.done += 1
async def display_status(self):
while self.running():
await asyncio.sleep(1)
print('\rdone:', self.done)
async def display_spinner(self, char=cycle('/|\-')):
while self.running():
print('\r' + next(char), flush=True, end='')
await asyncio.sleep(.3)
with closing(asyncio.get_event_loop()) as loop:
batch = Batch(10)
loop.run_until_complete(asyncio.wait([
batch.run(), batch.display_status(), batch.display_spinner()]))
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done: 0
done: 2
done: 3
done: 4
done: 10
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